Solve the following problems. Use the AGONSA Method. 1.)A lot in the shape of a parallelogram has a base of 40 meters and a height of 45 meters. What is its area? 2.)A triangular playground has a base of 22 meters and a height of 10 meters. Find its area. 10
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- $$1800 \text{ meters}^{2}$$ 1800 meters 2
- $$110 \text{ meters}^{2}$$ 110 meters 2
Explanation
Calculate the area of the parallelogram using the formula for the area of a parallelogram, which is $$\text{Area} = \text{base} \times \text{height}$$ Area = base × height . For the given base of 40 meters and height of 45 meters, the area is $$40 \times 45 = 1800 \text{ meters}^{2}$$ 40 × 45 = 1800 meters 2
Calculate the area of the triangular playground using the formula for the area of a triangle, which is $$\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$$ Area = 2 1 × base × height . For the given base of 22 meters and height of 10 meters, the area is $$\frac{1}{2} \times 22 \times 10 = 110 \text{ meters}^{2}$$ 2 1 × 22 × 10 = 110 meters 2
Note: The OCR answer for the second problem is incorrect. The correct area of the triangular playground is $$110 \text{ meters}^{2}$$ 110 meters 2 , not $$10 \text{ meters}^{2}$$ 10 meters 2 . The OCR error has been corrected in the rewrite_answer section
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