case study questions for class 6 maths chapter 1

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Class 6 Maths Chapter 1 Question and Answers

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case study questions for class 6 maths chapter 1

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Class 6 Maths Chapter 1 Important Questions – Knowing Our Numbers

Maths is an important subject we study in school. In Class 6, students will learn the basics of the subject, which will be needed in higher classes. The first chapter is about learning numbers. Maths deals with numbers, and students must identify numbers.

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In this chapter, students will study larger numbers like thousands, lakhs, etc. They will learn how to express these numbers with the help of commas. The chapter also includes addition and subtraction of larger numbers, how to find the largest among given numbers, etc. This is an easy chapter, but students must practice questions to build their concepts.

Extramarks is a leading company that provides all the important study materials related to CBSE and NCERT. Our experts have made the Important Questions Class 6 Maths Chapter 1 to help the students in practice. They have collected the questions from the textbook exercises, CBSE sample papers, CBSE past years’ question papers, NCERT Exemplars, and important reference books. They have solved the questions, and experienced professionals have further checked the answers to ensure the best quality of the content.

We provide a wide range of study materials to students, and you can download these after registering on our official website. You will find the CBSE syllabus, CBSE sample papers, CBSE revision notes, CBSE extra questions, CBSE past years’ question papers, NCERT books, NCERT solutions, NCERT Exemplars, NCERT important questions, vital formulas, and many more.

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Knowing Our Numbers Class 6 Extra Questions with Solutions

Our experts have made the question series to help students. They have collected the questions from textbook exercises, CBSE sample papers, CBSE past years’ question papers, NCERT Exemplars, and important reference books. They have also solved the questions so that students can follow the answers. Experienced professionals have further checked the solutions to ensure the best quality of the content. Thus, the Important Questions Class 6 Maths Chapter 1 will help students score better in exams. The important questions are-

Question 1.

Fill in the blanks:

(i) One lakh = ………….. ten thousand.

(ii) 1 million = ………… hundred thousand.

(iii) 1 crore = ………… ten lakh.

(iv) 1 crore = ………… million.

(v) 1 million = ………… lakh.

(i) 1 lakh = ten ten thousand.

(ii) 1 million = ten hundred thousand.

(iii) 1 crore = ten ten lakh

(iv) 1 crore = ten million

(v) 1 million = ten lakh

Question 2.

(i) 1 metre = ____millimetres.

(ii) 1 centimetre = ____ millimetres.

(iii) 1 kilometre = ____ millimetres.

(iii) 10, 00, 000

Question 3.

(i) 1 gram = ___ milligrams.

(ii) 1 litre = ___ millilitres.

(iii) 1 kilogram = ___ milligrams.

(iii) 10,00,000

Question 4.

Place the commas correctly and write the numerals :

(i) Seventy-three lakh seventy-five thousand three hundred seven.

(ii) Nine crore five lakh forty-one.

(iii) Seven crore fifty-two lakh twenty-one thousand three hundred two.

(iv) Fifty-eight million four hundred twenty- three thousand two hundred two.

(v) Twenty-three lakh thirty thousand ten.

(i) 73,75,307

(ii) 9,05,00,041

(iii) 7,52,21,302

(iv) 5,84,23,202

(v) 23,30,010.

Question 5.

Insert commas in the numbers suitably and write their names according to the Indian System of Numeration:

(i) 87595762

(ii) 8546283

(iii) 99900046

(iv) 98432701

(i) 8,75,95,762 (Eight crore seventy-five lakh ninety-five thousand seven hundred sixty- two)

(ii) 85,46,283 (Eighty-five lakh forty-six thousand two hundred eighty-three)

(iii) 9,99,00,046 (Nine crore ninety-nine lakh forty-six)

(iv) 9,84,32,701 (Nine crores eighty-four lakh thirty-two thousand seven hundred one)

Question 6.

Insert commas in the numbers suitably and write their names according to the International System of Numeration:

(i) 78921092

(ii) 7452283

(iii) 99985102

(iv) 48049831

(i) 78,921,092 (Seventy-eight million nine hundred twenty-one thousand ninety-two)

(ii) 7,452,283 (Seven million four hundred fifty- two thousand two hundred eighty-three)

(iii) 99,985,102 (Ninety-nine million nine hundred eighty-five thousand one hundred two)

(iv) 48,049,831 (Forty-eight million forty-nine thousand eight hundred thirty-one)

Question 7.

A number in which the Sum of all of its factors is equal to twice the number is called a ___ number.

Question 8.

The numbers which have more than just two factors are called ___ numbers.

Question 9.

Two is the only ___ number which is even.

Question 10.

Two numbers having only one as a common factor are called ___ numbers.

Question 11.

The Lowest Common Multiple ( LCM) of two or more given numbers is always the lowest of their common ___.

Question 12.

The Highest Common Factor (HCF) of two or more than two given numbers is also known as the highest of their common ___.

Question 13.

The product of the place values of the two 2’s in 428721 is

(iii) 400000

(iv) 40000000

(iii): Place the values of 2’s in 428721 are 20000 and 20

∴ The required product = 20000 × 2 = 400000

Question 14.

Number 3 × 10000 + 7 × 1000 + 9 × 100 + 0 × 10 + 4 is the same as

(iii) 37904

(iv) 379409

(ii) : 3 × 10000 + 7 × 1000 + 9 × 100 + 0 × 10 + 4

= 30000 + 7000 + 900 + 4 = 37904

Question 15.

If one is added to the greatest 7-digit number, then it will be equal to

(i) 10 thousand

(ii) 1 lakh

(iii) 10 lakh

(iv) One crore

(iv) : The greatest 7-digit number = 99,99,999

Now, 99,99,999 + 1 = 1,00,00,000

Question 16.

The greatest number in which on rounding off to the nearest thousands gives 5000, is

(iv) : (1) Rounding off 5001 to nearest thousands = 5000

(2) Rounding off 5559 to nearest thousands = 6000

(3) Rounding off 5999 to nearest thousands = 6000

(4) Rounding off 5499 to nearest thousands = 5000

And 5499 > 5001

Question 17.

Keeping the place of six in the number 6350947 same, the smallest number which can be obtained by rearranging other digits is

(i) 6975430

(ii) 6043579

(iii) 6034579

(iv) 6034759

(iii) : Tire new number formed = 6034579

Question 18.

The smallest four-digit number having three different digits is

(iv): The smallest 4-digit number with three different digits is 1002.

Question 19.

The number of all the whole numbers between 38 and 68 is

(iii): There are 29 whole numbers between 38 and 68.

Question 20.

The product of the successor and the predecessor of 999 is

(ii) 998000

(iii) 989000

(ii) : Successor of the number 999 = 999 + 1 = 1000

Predecessor of the number 999 = 999 – 1 = 998

Hence, their product = 998 1000 = 998000

Question 21.

Write in expanded form :

(ii) 574021

(iii) 8907010

(i) 74836 is equal to = 7 × 10000 + 4 × 1000 + 8 × 100 + 3 × 10 + 6 × 1

(ii) 574021 is equal to = 5 × 100000 + 7 × 10000 + 4 x 1000 + 0 × 100 + 2 × 10 + 1 × 1

(iii) 8907010 is equal to = 8 × 1000000 + 9 × 100000 + 0 × 10000 + 7 × 1000 + 0 × 100 + 1 × 10 + 0 × 1

Question 22.

A book exhibition was held for 4 days in a school. The number of the tickets sold on the counter on the first, second, third, and the final day was – 1094, 1812, 2050, and 2751. Find the total number of tickets that sold on all four days.

Number of the tickets sold on the first day = 1094

Number of the tickets sold on the second day = 1812

Number of the tickets sold on the third day = 2050

Number of the tickets sold on the final day = 2751

∴Total number of the tickets sold on all of these four days = 1094 + 1812 + 2050 + 2751 = 7,707.

Question 23.

Shekhar is a famous cricket player. He has so far scored a total of 6980 runs in test matches. He wishes to complete 10,000 runs. How many more runs does he need?

Shekhar has so far scored a total of 6980 runs

He wishes to complete a total of 10,000 runs.

Therefore total number of the runs needed by him are = 10,000 – 6980 = 3020 runs

Question 24.

Which of the following given statements is not true?

(i) Both the addition and multiplication are associative for whole numbers.

(ii) Zero is the identity for the multiplication of whole numbers.

(iii) Addition and multiplication are commutative for whole numbers.

(iv) Multiplication is distributive over addition for whole numbers.

(ii): Zero is the identity for the addition of whole numbers.

Question 25.

(i) 0 + 0 = 0

(ii) 0 – 0 = 0

(iii) 0 × 0 = 0

(iv) 0 – 0 = 0

(iv) : 0 + 0 is not defined.

Question 26.

The predecessor of 1 lakh is

(iii) 999999

(iv) 100001

(ii) : 1 lakh = 100000

∴ Predecessor of 100000 = 100000 – 1 = 99999

Question 27.

The successor of 1 million is

(i) Two million

(ii) 1000001

(iii) 100001

(ii) : 1 million = 1000000

∴ Successor of 1000000 = 1000000 + 1 = 1000001

Question 28.

The number of all the even numbers between 58 and 80 is

(i) : Even numbers between the numbers 58 and 80 are 60, 62, 64, 66, 68, 70, 72, 74, 76, 78.

So, these are ten even numbers between 58 and 80.

Question 29.

The Sum of the number of primes numbers between 16 to 80 and between 90 to 100 is

(iii) : Prime numbers between 16 to 80 are – 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73 and 79.

So, there are total 16 prime numbers between 16 to 80.

Also, 97 is the only one prime number between 90 to 100.

So, there is only one prime number between 90 to 100.

∴ Required sum = 16 + 1 = 17

Question 30.

(i) The HCF of the two distinct prime numbers is 1

(ii) The HCF of two coprime numbers is 1

(iii) The HCF of two consecutive even numbers is 2

(iv) The HCF of an even number and an odd number is always even

(iv): The HCF of an even and an odd number is always said to be an odd number.

Question 31.

In an election, the successful candidate was registered 5,77,500 votes, and his nearest rival had secured 3,48,700 votes. By what total margin did the successful candidate win the election?

Number of the votes secured by the successful candidate = 5,77,500

Number of the votes secured by his nearest rival = 3,48,700

Therefore, margin of the votes is necessary to win the election = 5,77,500 – 3,48,700 = 2,28,800

Question 32.

Kirti bookstore sold books worth a total of ₹2,85,891 in the 1st week of June and books worth a total of ₹4,00,768 in the second week of the month. How much was the total sale for the two weeks together? And in which week was the total sale greater and by how much?

Books sold in the first week of the month June are worth ₹2,85,891

Books sold in the second week of the month are worth ₹4,00,768

Therefore, the total sale of the books in the two weeks together is

= ₹2,85,891 + ₹4,00,768 = ₹6,86,659

In the 2nd week of the month, the sale of total books was greater.

Therefore, the difference in the sale of books

= ₹4,00,768 – ₹2,85,891 = ₹1,14,877

So, in the second week of June, the total sale of books was more than ₹1,14,877.

Question 33.

Find the difference below between the highest and the lowest numbers that is written using the digits 6, 2, 7, 4, and 3, each only once.

Given digits = 6, 2, 7, 4, 3

Greatest number is = 76432

Least number is = 23467

Therefore, difference = 76432 – 23467 = 52,965

Question 34.

A machine, on average, manufactures 2,825 screws a day. How many screws did it produce in January 2006?

The number of screws that are manufactured in a day = 2,825.

Number of screws that are manufactured in month of January = 31 x 2825 = 87,575

Question 35.

The total distance between the school and the house of a student is 1 km and 875 m. Every day she walks both the ways. Find the total distance she covered in six days.

Distance between the school and her house = 1 km 875 m = (1000 + 875) m = 1875 metre.

Total Distance travelled by the student from school to home and from home to school is = 2 x 1875 = 3750 m

Distance travelled by the student in six days is = 3750 m x 6 – 22500 m = 22 km 500 m.

Therefore, the total distance covered in 6 days = 22 km 500 m.

Question 36.

A merchant had ₹78,592 with her. She placed an order to purchase 40 radio sets at ₹1200 each. How much total money will remain with her after the purchase?

Amount of money present with the merchant = ₹78,592

Total Number of the radio sets = 40

Price of one of the radio set = ₹1200

Therefore, the cost of 40 radio sets = ₹1200 x 40 = ₹48,000

Remaining money left with the merchant = ₹78,592 – ₹48000 = ₹30,592

Hence, the amount of ₹30,592 will remain with her after purchasing the following radio sets.

Question 37.

A vessel has four litres and 500 ml of curd. How many total glasses, each of 25 mL capacity, can be filled?

Quantity of the curd in a vessel = 4 l 500 mL = (4 x 1000 + 500) mL = 4500 mL.

Capacity of 1 glass = 25 mL

Therefore the number of glasses = 4500/25

Question 38.

A student has multiplied the number 7236 by 65 instead of multiplying by 56. Calculate by how much was his answer greater than the right answer?

The student had multiplied the number 7236 by 65 instead of multiplying by 56.

The difference between the two above multiplications is = (65 – 56) x 7236 = 9 x 7236 = 65124

(We don’t have to do both the multiplication)

Hence, the answer that is greater than the correct answer is 65,124.

Question 39.

Estimate each of the following given numbers using the general rule:

(i) 730 + 998

(ii) 796 – 314

(iii) 12,904 + 2,888

(iv) 28,292 – 21,496

Rounding off 730 nearest to hundreds = 700

Rounding off 998 nearest to hundreds = 1,000

∴ 730 + 998 = 700 + 1000 = 1700

Rounding off 796 nearest to hundreds = 800

Rounding off 314 nearest to hundreds = 300

∴ 796 – 314 = 800 – 300 = 500

Rounding off 12,904 nearest to thousands = 13000

Rounding off 2888 nearest to thousands = 3000

∴ 12,904 + 2,888 = 13000 + 3000 = 16000

Rounding off 28,292 nearest to thousands = 28,000

Rounding off 21,496 nearest to thousands = 21,000

∴ 28,292 – 21,496 = 28,000 – 21,000 = 7,000

Question 40.

Estimate the following given products using the general rule:

(i) 578 x 161

(ii)5281 x 3491

(iii) 1291 x 592

(iv) 9250 x 29

(i) 578 x 161 = 600 x 200 = 1,20,000

(ii) 5281 x 3491 = 5000 x 3000 = 1,50,00,000

(iii) 1291 x 592 = 1300 x 600 = 7,80,000

(iv) 9250 x 29 = 9000 x 30 = 2,70,000

Question 41.

Which of the following is not true?

(i) (7 + 8) + 9 = 7 + (8 + 9)

(ii) (7 × 8) × 9 = 7 × (8 × 9)

(iii) 7 + 8 × 9 = (7 + 8) × (7 + 9)

(iv) 7 × (8 + 9) = (7 × 8) + (7 × 9)

(iii) : 7 + 8 × 9 = 7 + 72 = 79,

(7 + 8) × (7 + 9) = 15 × 16 = 240

and 79 ≠ 240

Question 42.

The length of the river ‘Narmada’ is 1290 km. Its length in metres is – _____.

As, 1290 km = (1290 × 1000) m = 1290000 m

Question 43.

The total distance between Srinagar and Leh is 422 km. The same distance in metres is – _____.

As, 422 km= (422 × 1000) m = 422000 m

Question 44.

Writing numbers from the greatest to the smallest is called an arrangement in ___ order.

Question 45.

By reversing the order of the digits of the greatest number made by the five different non-zero digits, we get the new number which is the number of _____ five digits.

By reversing the order of the digits of the greatest number made by the five different non-zero digits, the new number present is the smallest number of these digits.

Question 46.

By adding 1 to the greatest ___ digit number, we get the number ten lakh.

As, greatest six-digit number = 999999

By adding one to 999999, we get 1000000.

Question 47.

The number five crore twenty-three lakh seventy-eight thousand four hundred one can also be written, using the commas, in the Indian System of Numeration as.

5, 23, 78, 401

Question 48.

In the Roman Numeration, the symbol X can be subtracted from – ___, M and C only.

Question 49.

The number 66 in Roman numerals is.

LXVI : 66 = LXVI

Question 50.

The total population of Pune was 2,538,473 in 2001. Rounded off to the nearest thousands, the population was ___.

Question 51.

The smallest whole number is ___.

0 : 0 is the smallest whole number.

Question 52.

The successor of number 106159 is ___.

As, Successor of 106159 is 106159 + 1, i.e., 106160

Question 53.

400 is the predecessor of the number ___.

As, 400 is the predecessor of 400 + 1, i.e., 401

Question 54.

___ is the successor of the largest three digit number.

As, Largest three digit number = 999

And the successor of 999 is 999 + 1, i.e., 1000

Question 55.

If the number 7254*98 is to be divisible by the number 22, then the digit at * is

(iii) : 7254 * 98 is divisible by the number 22 only if it is divisible by both 2 and 11.

Given that the number is even. Therefore it is divisible by the number 2.

7254 * 98 is divisible by 11, only if

(7 + 5 + * + 8) – (2 + 4 + 9) or (20 + *) – 15 or 5 + * is also divisible by 11.

∴ The digit at * place should be filled by 6.

Question 56.

The largest number which will always divide the Sum of any pair of consecutive odd numbers is

(ii)The Sum of any pair of the consecutive odd numbers results in the form of a multiple of 4.

∴ The required largest number is 4.

Question 57.

A number is divisible by five and six. It may not be divisible by

(iv): The Least Common Multiple also known as LCM of 5 and 6 is 30.

And also 30 is divisible by the numbers 10, 15 and 30 but not by the number 60.

Question 58.

The greatest number which will always divide the product of the predecessor and successor of an odd natural number other than 1, is

(ii): As the odd natural numbers other than 1 are – 3, 5, 7, 9 and so on.

Now, we know that the predecessor and successor of 3 are – 2 and 4 respectively, and their product is two × four = 8

Similarly, we know that the predecessor and the successor of 5 are – 4 and 6, respectively, and their product is four × 6 = 24.

Thus, the above shows that the greatest number which always divides the product of the predecessor and the successor of an odd natural number other than 1 is 4.

Question 59.

A person had only ₹ 1000000 with him. He purchased a coloured-T.V. for ₹ 16580, a motorcycle for ₹ 45890 and a flat for ₹ 870000. How much money was left with him?

The total amount a person had was = ₹ 1000000

The total amount he spent on a colour T.V. was = ₹ 16580

The amount he spent on a motorcycle was = ₹ 45890

The amount he spent on a flat was = ₹ 870000

∴ Total amount he spent is = ₹ (16580 + 45890 + 870000) = ₹ 932470

Thus, the total amount left with him = ₹ 1000000 – ₹ 932470 = ₹ 67530

Question 60.

Out of 180000 tablets of Vitamin A, a total of 18734 are distributed among the students in the district. Find the total number of remaining vitamin tablets.

Total tablets of Vitamin A are = 180000

Total number of tablets distributed among the students in the district = 18734

∴ The number of total remaining vitamin tablets = 180000 – 18734 = 161266

Question 61.

Chinmay only had ₹ 610000. He gave a total of ₹ 87500 to Jyoti, ₹ 126380 to Javed and ₹ 350000 to John. How much money was left with him?

Chinmay had a total amount = of ₹ 610000

The total amount he gave to Jyoti = ₹ 87500

The total amount he gave to Javed = ₹ 126380

The total amount he gave to John = ₹ 350009

Total amount given by Chinmay is = ₹ (87500 + 126380 + 350000) = ₹ 563880

Thus, the amount left with him

= ₹ 610000 – ₹ 563880 = ₹ 46120

Benefits of Solving Class 6 Maths Chapter 1 Extra Questions

Practise is very important, and it helps students in several ways. Our experts have made the question series to help students in practise. Thus, the questions will help students in several ways, and they will be worthy of their time. The benefits of solving the Important Questions Class 6 Maths Chapter 1 are as follows-

The experts have collated the questions from different sources. They have taken help from the textbook exercises, CBSE sample papers, CBSE past years’ question papers, NCERT Exemplars and important reference books. Thus, students don’t have to search for questions in different sources: they will find them in a single pdf. Thus, the Class 6 Maths Chapter 1 Important Questions will help them in practise and boost their confidence.
The experts have not only collected the questions, but they have also provided the solutions. Thus, students can follow the solution if they cannot solve the questions. Also, they can check their answers with the provided explanations. Thus, the Maths Class 6 Chapter 1 Important Questions will help students boost their confidence and improve their exam preparation.
Many students tend to fear maths because they don’t understand the subject. Their doubts must be cleared, and practice can help boost confidence. They must build the habit of solving questions to build interest in the subject matter. The experts have done a good job of collating the questions for students. They can solve these questions regularly, which will help them improve their knowledge. Thus, the Chapter 1 Class 6 Maths Important Questions will improve their exam preparation.

Extramarks is a leading company that provides all the important study materials related to CBSE and NCERT. We provide the CBSE syllabus, CBSE sample papers, CBSE past years’ question papers, CBSE revision notes, CBSE extra questions, NCERT books, NCERT Exemplars, NCERT solutions, NCERT important questions, vital formulas, and many more. Like the Important Questions Class 6 Maths Chapter 1, you will also find important questions for other chapters. The links to the study materials are given below.

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Q.1 Which of the following is the representation of number 74 according to roman numerals?

(b). XXXXXXXIV

(d). DCCXLV

Ans (a). LXXIV

Q.2 What is the greatest 7 digit number formed by using the digits 4 , 9 , 1 and 6? Note that each digit should be used at least once.

(a). 99,99,641

(c). 99,66,441

(d). 11,11,469

Given digits:

9 > 6 > 4 > 1

The greatest 7 digit number using the digits 4, 9, 1 and 6 is 99,99,641.

Q.3 Which one of the following is the estimated product of 47 and 215?

Rounding off 215 to the nearest hundreds, we get 200.

Rounding off 47 to nearest tens, we get 50.

Estimated product

Thus, 10,000 is the estimated product of 47 and 215.

Q.4 Write 645340001 using comma in International System of Numeration.

645,340,001

Q.5 a) How many thousands make a million? b) How many lakhs make a crore?

a) 1000 thousands make 1 million. (? 1 million = 1,000,000 = 1000 thousands) b) 100 lakhs make a crore. (? 1 crore = 1,00,00,000 = 100 lakhs)

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Cbse important questions for class 6 maths, chapter 2 - whole numbers.

Chapter 3 - Playing with Numbers

Chapter 4 - basic geometrical ideas, chapter 5 - understanding elementary shapes, chapter 6 - integers, chapter 7 - fractions, chapter 8 - decimals, chapter 9 - data handling, chapter 10 - mensuration, chapter 11 - algebra, chapter 12 - ratio and proportion, chapter 13 - symmetry, chapter 14 - practical geometry, faqs (frequently asked questions), 1. is class 6 maths chapter 1 easy.

The first chapter of Class 6 Maths provides a few basic ideas related to numbers. They will learn how to express bigger numbers, such as in thousands, lakhs, crores, etc. They will also learn how to use commas to write larger number, add or subtract large numbers, etc. This is an easy chapter because most students have ideas regarding lakhs, crores, or other units of numbers. Thus, students won’t have problems understanding the subject matter if they follow the textbook closely. Students can take help from the Important Questions Class 6 Maths Chapter 1 prepared by the experts of Extramarks, and they will find a wide variety of questions to solve.

2. How can the question series help students?

Practice is very important for getting better marks in exams. Sometimes, more than the textbook exercises are needed, and students should get help from other sources. The experts of Extramarks have made the question series with help from different sources. They have collated the questions from the textbook exercise, CBSE sample papers, CBSE past years’ question papers, and important reference books. They have solved the questions, and experienced professionals have further checked the answers to ensure the best quality of the content. Thus, the Important Questions Class 6 Maths Chapter 1 will help students score better in exams. It will also help boost their confidence and incline interest in the subject matter.

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NCERT Solutions Class 6 Maths Chapter 1 Knowing Our Numbers

NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers will help the students take their understanding of numbers a bit further and explore topics like shifting digits, expanding brackets, roman numerals, estimating sum or difference, products, outcomes of number situations, and many more. This chapter will also help the students revise all the operations on numbers like multiplication , addition , subtraction , and division covered in the previous classes. Presented below is an in-depth analysis of Class 6 Maths NCERT Solutions Chapter 1.

These solutions will help the students understand large numbers through real-life examples while also exploring their unit conversions. They will also get to learn about the International and Indian systems of numeration along with an introduction to the concept of roman numerals. Let us now take a deeper look at the different sub-topics covered in NCERT Solutions Class 6 Maths Chapter 1 and also you can find some of these in the exercises given below.

NCERT Solutions Class 6 Maths Chapter 1 Ex 1.1
NCERT Solutions Class 6 Maths Chapter 1 Ex 1.2
NCERT Solutions Class 6 Maths Chapter 1 Ex 1.3

NCERT Solutions for Class 6 Maths Chapter 1 PDF

NCERT Solutions Class 6 Maths Chapter 1 Knowing Our Numbers contains all the important questions, images, explanations, and formulas covered in the chapter. These solutions are aimed at helping the students understand and solve complex concepts such as the use of commas in larger numbers. Commas are used to mark thousands, lakhs, and crores. Let us do a detailed exercise-wise overview of this chapter using the PDF links given below :

☛ Download Class 6 Maths NCERT Solutions Chapter 1 Knowing Our Numbers

NCERT Class 6 Maths Chapter 1 Download PDF

NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers

Students must have already studied the formation of numbers in the previous classes. In this chapter, they will be introduced to the concept of arranging numbers in ascending as well as in descending order and shifting the digits to form new numbers. All these ideas are explained along with real-life examples in the NCERT Solutions Class 6 Maths Chapter 1 Knowing Our Numbers.

Class 6 Maths Chapter 1 Ex 1.1 - 4 Questions
Class 6 Maths Chapter 1 Ex 1.2 - 12 Questions
Class 6 Maths Chapter 1 Ex 1.3 - 5 Questions

☛ Download Class 6 Maths Chapter 1 NCERT Book

Topics Covered: The important topics covered under Class 6 maths NCERT Solutions Chapter 1 are natural numbers , comparison of numbers, place value of a digit, estimation of the numbers, roman numerals , and importance of brackets. Questions related to all these topics must be practiced regularly to score excellent marks in the exams.

Total Questions: Class 6 Maths Chapter 1 Knowing Our Numbers has a total of 21 well-researched questions out of which 12 are straightforward, 3 are of moderate level, and 6 are complex level problems.

List of Formulas in NCERT Solutions Class 6 Maths Chapter 1

NCERT solutions class 6 maths chapter 1 does not cover any formulas . However, there are some pointers that the students must remember while solving problems from this chapter. These pointers will help them avoid mistakes while giving a crystal clear understanding of the topics covered in this chapter. Let us now go through these pointers one by one :

Given two numbers, if one has a large number of digits, then it is greater. In the case where the number of digits is the same, the number with the larger leftmost digit is considered to be the greater number.
We put commas after 3 digits in the Indian system. These commas are put after 3,5,7, thus separating the thousand, lakh, and crore. However, in the International System, we put commas after every 3 and 6 digits from right, separating thousands, billions, and further billions.
We use estimation in order to get a rough figure of the numbers involved. This gives us a quick idea of the answer. Estimation is done by rounding numbers.

Important Questions for Class 6 Maths NCERT Solutions Chapter 1

Faqs on ncert solutions for class 6 maths chapter 1, why are ncert solutions class 6 maths chapter 1 important.

NCERT Solutions Class 6 Maths Chapter 1 will help kids identify pain points and find ways to solve questions in an efficient manner. They focus on some of the fundamental concepts that act as a building block for a kid’s mathematical journey. Topics such as estimation have practical applications in our daily life as it gives an idea of the quantity. Thus these solutions are extremely important for students considering their utility in everyday life.

Do I Need to Practice all Questions Provided in NCERT Solutions for Class 6 Maths Knowing Your Numbers?

All the questions in NCERT Solutions are curated by experts covering a range of topics. NCERT Solutions for Class 6 Maths Chapter 1 will help you explore all the topics in detail by solving a range of problems. Thus practicing all the questions of this chapter is important for a strong mathematical foundation.

What are the Important Topics Covered in NCERT Solutions Class 6 Maths Chapter 1?

NCERT Solutions Class 6 Maths Chapter 1 covers a range of essential topics such as estimating numbers, use of commas, place value, expanding brackets, and roman numerals. Questions related to all these topics are explained in a step-wise manner in the NCERT solutions.

How Many Questions are there in Class 6 Maths NCERT Solutions Chapter 1 Knowing Your Numbers?

There are a total of 21 sums in the NCERT Solutions Class 6 Maths Chapter 1 Knowing Your Numbers. These questions are distributed in 3 exercises. Out of 21 questions, 10 are easy sums, 5 are moderately difficult problems, while 6 are complex sums that need brainstorming.

How can CBSE Students utilize NCERT Solutions for Class 6 Maths Chapter 1 effectively?

In order to effectively utilize the NCERT Solutions Class 6 Maths Chapter 1 students must go through the detailed solutions of all the questions, explore the chapter summary, and theory of the chapter. Students must give adequate time to all the exercises and solve questions in a step-wise manner.

Why Should I Practice NCERT Solutions Class 6 Maths Knowing Your Numbers?

NCERT Solutions Class 6 Maths Chapter 1 Knowing Your Numbers will help you revise the previous concepts from earlier classes like place values, whole numbers, number system, etc. Apart from that, this chapter will help you understand the applications of interesting concepts in your day-to-day life.

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NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers

NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers are discussed here in detailed. Numbers are very important for real life as well as for Mathematics. In NCERT textbook for Class 6 chapter 1, students can learn Indian arrangement of numeration, the universal arrangement of numeration, learn large numbers up to 1 crore (10000000), estimation of large numbers and roman numerals. CBSE NCERT Solutions for Class 6 Maths are covering the solutions for the problems from all the concepts. In NCERT Solutions for Class 6 Math chapter 1, there is a total of 19 questions in 3 exercises.

Latest: Important Maths Formulas for Class 6 - Chapterwise

NCERT Solutions for Class 6 Maths Chapter 1 - Important Formula

Ncert solutions for class 6 maths chapter 1 - important topics, ncert solutions for class 6 maths chapter 1 knowing our numbers (intext questions and exercise), ncert solutions for class 6 maths chapter 1 - exercise 1.1, ncert solutions for class 6 maths chapter 1 - exercise 1.2, ncert solutions for class 6 maths chapter 1 - exercise 1.3, ncert solutions for class 6 maths chapter 1 - topics, ncert solutions for class 6 maths - chapter-wise, key features of ncert solutions for class 6 maths chapter 1.

$NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers$

NCERT 6th Class solutions are covering all the answers or solutions in a very comprehensive manner. CBSE NCERT solutions for Class 6 Maths chapter 1 also provides assistance in solving the practice problems. Along with NCERT Class 6 Maths solutions, students can check the NCERT solutions for other subjects prepared based on NCERT syllabus.

Natural numbers: 1, 2, 3, 4, and so forth.

Sum of first n natural numbers = n(n+1)/2

A number is formed by combining digits, which can only be 0, 1, 2, 3, 4, 5, 6, 7, 8, or 9.

Place Value of a digit in a number = Face Value × Position Value

When comparing two numbers, the one with more digits is always greater. If two numbers have the same digit, the comparison starts from the leftmost digit.

To create the smallest number, begin with 1 in the leftmost position and add zeroes. For instance, the smallest four-digit number is 1000.

To create the largest number, start with 9 in the leftmost position. For example, the largest four-digit number is 9999.

There are specific quantity weights for conversions, such as:

1 kilometre (km) = 1000 metres (m)

1 metre (m) = 100 centimetres (cm)

1 centimetre (cm) = 10 millimetres (mm)

1 kilogram (kg) = 1000 grams (gm)

1 litre (l) = 1000 millilitres (ml)

Roman numerals are another system of representation, where each symbol corresponds to a specific value:

In Roman numerals, you can perform subtraction or addition by placing the desired quantity to the left or right. For example, 21 can be written as XXI, and 49 can be written as ILIX.

Place Value: Place value refers to the value of a digit based on its position in a number. It helps understand the significance of each digit and determines the overall value of a number.

Comparing Numbers: Comparing numbers involves determining the relationship between two or more numbers, whether they are equal, greater than, or less than each other. It helps in understanding the order and magnitude of numbers.

Estimation: Estimation is the process of making approximate calculations or predictions based on available information. It helps in getting a quick idea of the magnitude or value of a number or quantity without performing precise calculations.

Rounding Off: Rounding off involves approximating a number to a specified place value. It simplifies numbers and makes them easier to work with by reducing the number of digits while retaining a reasonable degree of accuracy.

Brackets: Brackets are symbols used in mathematical expressions to indicate grouping or prioritizing operations. They help in clarifying the order of operations and ensure correct calculation.

Roman Numerals: Roman numerals are a numeral system used in ancient Rome. They use specific symbols to represent different values, such as I, V, X, L, C, D, and M. Understanding Roman numerals helps in interpreting historical dates, numbering lists, and understanding some traditional numeral systems.

Free download NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers PDF for CBSE Exam.

Download PDF

Knowing Our Numbers Class 6 NCERT Topic-Comparing Numbers

Q1 Can you instantly find the greatest and the smallest numbers in each row? 2. 1473, 89423, 100, 5000, 310 3. 1834, 75284, 111, 2333, 450 4. 2853, 7691, 9999, 12002, 124

Answer: By Observing the number of digits and digit in the leftmost place can straight away tell us about the greatest and smallest number

(2) 1473, 89423, 100, 5000, 310

89423 is the greatest while 100 is the smallest

(3) 1834, 75284, 111, 2333, 450

75284 is the greatest 111 while is the smallest

(4) 2853, 7691, 9999, 12002, 124

12002 is the greatest while 124 is the smallest

Q2 Find the greatest and the smallest numbers. (a) 4536, 4892, 4370, 4452 (b) 15623, 15073, 15189, 15800 (c) 25286, 25245, 25270, 25210 (d) 6895, 23787, 24569, 24659

(a) 4536, 4892, 4370, 4452

4892 is the greatest while 4370 is the smallest

(b) 15623, 15073, 15189, 15800

15800 is the greatest while 15073 is the smallest (c) 25286, 25245, 25270, 25210

25286 is the greatest while 25245 is the smallest (d) 6895, 23787, 24569, 24659

24659 is the greatest while 6895 is the smallest

Knowing Our Numbers Class 6 NCERT Topic: Number Formation

Q1 Use the given digits without repetition and make the greatest and smallest 4-digit numbers. (a) 2, 8, 7, 4 (b) 9, 7, 4, 1 (c) 4, 7, 5, 0 (d) 1, 7, 6, 2 (e) 5, 4, 0, 3

(a) 2, 8, 7, 4

8742 is the greatest while 2478 is the smallest

(b) 9, 7, 4, 1

9741 is the greatest 1479 while is the smallest

4750 is the greatest while 4057 is the smallest

(d) 1, 7, 6, 2

7621 is the greatest while 1267 is the smallest

(e) 5, 4, 0, 3

5430 is the greatest while 3045 is the smallest

Q2 Now make the greatest and the smallest 4-digit numbers by using any one digit twice. (a) 3, 8, 7 (b) 9, 0, 5 (c) 0, 4, 9 (d) 8, 5, 1

(a) 3, 8, 7

8873 is the greatest while 3387 is the smallest

(b) 9, 0, 5

9950 is the greatest while 5009 is the smallest

9940 is the greatest while 4009 is the smallest

(d) 8, 5, 1

8851 is the greatest while 1158 is the smallest

Q3 Make the greatest and the smallest 4-digit numbers using any four different digits with conditions as given. (a) Digit 7 is always at one's place Greatest - 9 8 6 7 Smallest - 1 0 2 7 (Note, the number cannot begin with the digit 0. Why?) (b) Digit 4 is always at tens place Greatest - _ _ 4 _ Smallest - _ _ 4 _ (c) Digit 9 is always at hundreds place Greatest - _ 9 _ _ Smallest - _ 9 _ _ (d) Digit 1 is always at thousands place Greatest- 1 _ _ _ Smallest - 1 _ _ _

(b) Digit 4 is always at tens place Greatest - 98 47 Smallest - 10 42 (c) Digit 9 is always at hundreds place Greatest - 8 976 Smallest - 1 902

(d) Digit 1 is always at thousands place Greatest- 1987 Smallest - 1023

Q4 Take two digits, say 2 and 3. Make 4-digit numbers using both the digits an equal number of times. Which is the greatest number? Which is the smallest number? How many different numbers can you make in all?

Greatest number - 3322

Smallest number - 2233

Different numbers are

2222, 2232, 2233, 2322, 2333, 2332, 2323, 2223, 3222, 3223, 3232, 3233, 3322, 3333, 3332, 3323

There are 16 in total

Solutions For Knowing Our Numbers Class 6 NCERT Topic: Arrangement of Numbers

Q1 Arrange the following numbers in ascending order : (a) 847, 9754, 8320, 571 (b) 9801, 25751, 36501, 38802

(a) 847, 8320, 8320, 571

571 < 847 < 8320 < 8320

(b) 9801, 25751, 25751, 38802

9801 < 25751 < 25751 < 38802

Q2 Arrange the following numbers in descending order : (a) 5000, 7500, 85400, 7861 (b) 1971, 45321, 88715

(a) 5000, 7500, 85400, 7861

85400 > 7861 > 5000 > 75000

(b) 1971, 45321, 88715

88715 > 45321 > 1971

Solutions For Knowing Our Numbers Class 6 NCERT Topic-Revisiting Place Value

Q1 Read and expand the numbers wherever there are blanks.

1. 50000- ________________________________________ 2. 41000- ________________________________________ 3. 47300- ________________________________________ 4. 57630- ________________________________________

5. 29485________________________________________ 6. 29085________________________________________

1. 50000-Fifty thousand 2. 41000-forty one thousand 3. 47300- forty-seven thousand and three hundred 4. 57630- fifty-seven thousand six hundred

5. 29485- twenty-nine thousand and four hundred eighty-five 6. 29085- twenty-Nine Thousand and Eighty-Five

Q2 Read and expand the numbers wherever there are blanks.

4,57,928 _______________ _______________

4,07,928 _______________ _______________

4,00,829 _______________ _______________

4,00,029 _______________ _______________

4,57,928 Four Lakhs Fifty Seven Thousand and Nine Hundred Twenty Eight

4,07,928 Four Lakhs Seven Thousand and Nine Hundred Twenty-Eight

4,00,829 Four Lakhs Eight Hundred Twenty-Nine

4,00,029 Four Lakhs and Twenty-Nine

Q3 You have the following digits 4, 5, 6, 0, 7 and 8.

Using them, make five numbers each with 6 digits.

(a) Put commas for easy reading.

(b) Arrange them in ascending and descending order.

$4, 5, 6, 0, 7, 8$

Q1 Fill in the blanks:

(a) 1 lakh = _______ ten thousand.

(b) 1 million = _______ hundred thousand.

(d) 1 crore = _______ million.

(e) 1 million = _______ lakh.

Let us take this as a physical world problem:

You went to a shop and you bought a toy of Rs. 100. You checked your pocket and found many notes but of only Rs.10

How many Rs.10 notes will you give to shopkeeper:

Well, it’s simple.

You will pay 10 notes.

The similar easy approach can be done in all the blanks,

Hint: Always remember to keep your eyes on a number of zeros

(a)1 lakh= 100000

1thousand= 1000

Ten thousand= 10*1000 = 10000

1 lakh/ 10 thousand =100000/10000 =10

So, 1lakh= 10 ten thousand

(b) 1 million= 1000000

Hundred thousand= 100*1000 = 100000

1 million/ hundred thousand =1000000/100000 =10

So, 1milion= 10 hundred thousand

1lakh= 100000 (5 zeros)

Ten lakh= 10*1000 = 1000000( 6 zeros)

1 crore/ Ten lakh=10000000/1000000 =10

So, 1 crore= 10 Ten lakh

(d)1 crore= 10000000 (7 zeros)

1million= 100000 (6 zeros)

1 crore/ 1million=10000000/1000000 =10

So, 1 crore= 10 million

(e) 1 million= 1000000

1lakh= 100000

1million/ 10 lakh = 1000000/100000 =10

So, 1 million= 10 lakhs

See, all answers came out to be 10 but not everytime

Q2 Place commas correctly and write the numerals:

(a) Seventy three lakh seventy five thousand three hundred seven.

(b) Nine crore five lakh forty one.

(d) Fifty eight million four hundred twenty three thousand two hundred two.

(e) Twenty three lakh thirty thousand ten.

$73,75,307$

Q3 Insert commas suitably and write the names according to Indian System of Numeration :

(a) 87595762 (b) 8546283 (c) 99900046 (d) 98432701

$8,75,95,762$

NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers: Large Numbers in Practise

Q1 A box contains 2,00,000 medicine tablets each weighing 20 mg. What is the total weight of all the tablets in the box in grams and in kilograms? Answer:

$2,00,000$

(i) Total distance from A to D = AB + BC + CD

$= (4170 + 3410 + 2160)\ km = 9740\ km$

(ii) Total distance between D to G = DE + EF + FG

$= (8140 + 4830 + 2550)\ km = 15520\ km$

(iii) Required distance = AD + DG + GA

$= (4170 + 3410 + 2160 + 8140 + 4830 + 2550 + 1290)\ km = 26550 km$

Q1 A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final day was respectively 1094, 1812, 2050 and 2751. Find the total number of tickets sold on all the four days.

Answer: Given,

Tickets sold on the first day of exhibition = 1094
Tickets sold on the second day = 1812
Tickets sold on the third day = 2050
Tickets sold on the last day = 2751
Total number of tickets sold =

$\\ = 1094 + 1812 + 2050 + 2751 \\ = 7707$

Q2 Shekhar is a famous cricket player. He has so far scored 6980 runs in test matches. He wishes to complete 10,000 runs. How many more runs does he need?

The number of runs scored by Shekhar so far = 6980

The number of runs Shekhar wishes to score = 10,000

$\therefore$

Q3 In an election, the successful candidate registered 5,77,500 votes and his nearest rival secured 3,48,700 votes. By what margin did the successful candidate win the election?

Number of votes registered by the successful candidate = 5, 77,500 votes

Number of votes registered by the rival candidate = 3, 48,700 votes

$= 5,77,500 - 3,48,700$

Q4 Kirti bookstore sold books worth 2,85,891 in the first week of June and books worth 4,00,768 in the second week of the month. How much was the sale for the two weeks together? In which week was the sale greater and by how much?

$Rs \ 2,85,891$

Clearly, sales in the second week is greater than the first year by

$Rs.\ (4, 00,768 - 2, 85,891) = Rs.\ 1, 14,877$

Q5 Find the difference between the greatest and the least 5-digit number that can be written using the digits 6, 2, 7, 4, 3 each only once.

Given, digits: 6, 2, 7, 4 and 3

Since, the digits have to be used only once, arrange them in ascending and descending order to get the minimum and maximum number.

$76,432$

Q6 A machine, on an average, manufactures 2,825 screws a day. How many screws did it produce in the month of January 2006?

$2, 825$

We know, there are 31 days in January

$2, 825 \times 31$

Q7 A merchant had rupees 78,592 with her. She placed an order for purchasing 40 radio sets at rupees 1200 each. How much money will remain with her after the purchase?

$Rs.\ 78, 592$

Q8 A student multiplied 7236 by 65 instead of multiplying by 56. By how much was his answer greater than the correct answer? (Hint: Do you need to do both the multiplications?)

$7236\ by\ 65$

Ques 9 - To stitch a shirt, 2 m 15 cm cloth is needed. Out of 40 m cloth, how many shirts can be stitched and how much cloth will remain? (Hint: convert data in cm.)

$(1\ m = 100\ cm)$

Therefore, 18 shirts can be made from the given cloth.

$130\ cm = 1\ m\ 30\ cm$

Ques 10- Medicine is packed in boxes, each weighing 4 kg 500g. How many such boxes can be loaded in a van which cannot carry beyond 800 kg?

$(1\ kg = 1000\ g)$

Hence, 177 boxes can be loaded in the van.

Ques 11- The distance between the school and a student’s house is 1 km 875 m. Every day she walks both ways. Find the total distance covered by her in six days.

$(1\ km = 1000\ m)$

Ques 12- A vessel has 4 litres and 500 ml of curd. In how many glasses, each of 25 ml capacity, can it be filled?

$(1\ l = 1000\ ml)$

Hence, 180 glasses are needed to fill the vessel completely.

NCERT Solutions for Class 6 Maths Chapter 1 - Estimating to the Nearest Thousand Rounding Off

Ques- 1 Round off the given numbers to the nearest tens, hundreds and thousands.

Given Number Approximate to Nearest Rounded Form 75847 Tens ________________ 75847 Hundreds ________________ 75847 Thousands ________________ 75847 Ten thousands ________________

Ques 1- Estimate each of the following using general rule (a) 730 + 998 (b) 796 – 314 (c) 12,904 +2,888 (d) 28,292 – 21,496

$730 + 998$

730 rounds off to 700,

998 rounds off to 1000.

$700+1000$

By rounding off to hundreds,

796 rounds off to 800,

314 rounds off to 300.

$800-300$

By rounding off to thousands,

2904 rounds off to 13000,

2822 rounds off to 3000.

$13000+3000$

By rounding off to nearest thousands,

28,296 rounds off to 28000,

21,496 rounds off to 21,000

$28,000 - 21,000$

Rounding off to nearest hundreds,

439 rounds off to 400

334 rounds off to 300

4317 rounds off to 4300,

$400+300+4300$

Again, by rounding off to nearest tens,

439 rounds off to 440

334 rounds off to 330

4317 rounds off to 4320,

$440+330+4320$

Also, rounding off to nearest tens,

$1, 08,730$

8325 rounds off to 8300

491 rounds off to 500

$8300 - 500$

8325 rounds off to 8330

491 rounds off to 490

$8330 - 490$

Ques 3- Estimate the following products using the general rule: (a) 578 × 161 (b) 5281 × 3491 (c) 1291 × 592 (d) 9250 × 29

$578\times161$

Rounding off by general rule,

578 rounds off to 600

161 rounds off to 200,

$600\times200$

Rounding off by the general rule,

5281 rounds off to 5000

3491 rounds off to 3500

$5000\times3500$

1291 rounds off to 1300

592 rounds off to 600

$1300\times600$

9250 rounds off to 10000

$10000 \times 30$

NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers- Topic Using Brackets

Ques 1- Write the expressions for each of the following using brackets. (a) Four multiplied by the sum of nine and two. (b) Divide the difference of eighteen and six by four. (c) Forty five divided by three times the sum of three and two.

(a) Four multiplied by the sum of nine and two.

$= 4\times(9+2) = 4\times11 = 44$

Ques 2- Write in Roman numerals. 1. 73 2. 92

$\\ 1.\ 73 - LXXIII \\ 2.\ 92 - XCII$

NCERT Solutions for Class 9 - Subject Wise

1.1 Introduction

1.2 Comparing Numbers

1.2.1 How many numbers can you make?

1.2.2 Shifting of numbers.

1.2.3 Introducing 10,000.

1.2.4 Revisiting place value.

1.2.5 Introducing 1,00,000.

1.2.6 Larger numbers.

1.2.7 An aid in reading and writing large numbers.

1.3 Large Numbers in Practice

1.3.1 Estimation

1.3.2 Estimating to the nearest tens by rounding off.

1.3.3 Estimating to the nearest hundreds by rounding off.

1.3.4 Estimating to the nearest thousands by rounding off.

1.3.5 Estimating outcomes of number situations.

1.3.6 To estimate sum or difference.

1.3.7 To estimate products.

1.4 Using Brackets

1.5 Roman Numerals

Expertly Crafted Solutions: The NCERT Solutions for Chapter 1 are carefully developed to provide clear and accurate explanations to all the problems and concepts discussed in the chapter.

Conceptual Clarity: The NCERT maths book class 6 chapter 1 solutions aim to enhance the conceptual understanding of students by breaking down complex topics into simpler and more understandable explanations.

Comprehensive Coverage: The maths class 6 chapter 1 cover all the important topics and subtopics of Chapter 1, ensuring that students have a complete understanding of the chapter.

Exam-Focused Approach: The ncert class 6 maths chapter 1 are designed with an exam-focused approach, providing students with the necessary tools and techniques to tackle questions effectively and score well in exams.

Also Check -

NCERT Books and NCERT Syllabus

NCERT Books Class 6 Maths
NCERT Syllabus Class 6 Maths
NCERT Books Class 6
NCERT Syllabus Class 6

Frequently Asked Question (FAQs)

NCERT Solutions for Class 6 Maths Chapter 1 - Knowing Our Numbers provide a comprehensive and student-friendly approach to learning mathematics, helping students build a strong foundation in the subject. There are 3 exercise including exercise 1 which has 4 questions, exercise 2 that has 12 questions and exercise 3 that has 3 questions. Students can practice these exercise to command the concepts.

Knowing Our Numbers is an important chapter from NCERT syllabus of Class 6. Students can download Knowing Our Numbers solutions to use it offline. they can study knowing our numbers class 6 pdf after download. On clicking the download button the complete page will be downloaded and can be used for offline preparation.

ncert class 6 maths chapter 1 solutions covers the following topics:

Introduction to numbers
Comparing numbers
Ascending order and descending order
Forming numbers using digits
Shifting digits
Place value
Larger numbers and estimates
Estimating sum or difference
Estimating products of numbers
Using brackets
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NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers

Get here the NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers and Class 6 Maths Chapter 1 Try These Solutions and Practice Tests for revision. It is given here in Hindi and English Medium prepared for academic session 2023-24. According to rationalised syllabus and new books for class 6 Mathematics for CBSE 2023-24, there are only two exercises in chapter 1 Knowing our numbers.

6th Maths Chapter 1 Solutions for CBSE Board

Class 6 Maths Chapter 1 Try These
Class 6 Maths Exercise 1.1 in English
Class 6 Maths Exercise 1.2 in English

6th Maths Chapter 1 Solutions for State Boards

Class 6 Maths Chapter 1 Exercise 1.1
Class 6 Maths Chapter 1 Exercise 1.2
Class 6 Maths Chapter 1 Exercise 1.3
Class 6 Maths Chapter 1 NCERT Book
Class 6 Maths Solutions Page
Class 6 all Subjects Solutions

Class 6 Maths Chapter 1 Knowing Our Numbers

Class 6 Maths Chapter 1 Practice Test 6th Maths Chapter 1 Test 1 6th Maths Chapter 1 Test 2 6th Maths Chapter 1 Test 3 6th Maths Chapter 1 Test 4 6th Maths Chapter 1 Test 5 6th Maths Chapter 1 Test 6

Get class VI Maths Exercise 1.1 and 1.2 at Tiwari Academy in simplified way. 6th Maths Solutions PDF and Video in English and Hindi Medium are prepared in such a way that student can understand it easily. We have updated it for new session based on latest textbooks from NCERT (https://ncert.nic.in/) website. Find the Solutions of Prashnavali 1.1 and 1.2 in Hindi. We are following the latest CBSE Syllabus 2023-24. We work for your help free of cost. Separate links are given to download solutions in PDF file format. In case of any hassle in finding the solutions, please inform us. We will help you at our level best.

These NCERT Solutions are based on latest CBSE – NCERT Textbooks for the CBSE exams 2023-24. Download NCERT Solutions in PDF format to use it offline or use as it is online without downloading.

In 6 Maths Chapter 1 Knowing Our Numbers, we will study about comparing the number (smaller or greater), selecting the smallest or greatest numbers, order of numbers (ascending or descending).

Ascending order: Ascending order means arrangement from the smallest to the greatest. Descending order: Descending order means arrangement from the greatest to the smallest.

Concepts of Place values, face values and questions based on the numbers as follow: Starting from the greatest 6-digit number, write the previous five numbers in descending order. Starting from the smallest 8-digit number, write the next five numbers in ascending order. The Indian System of Numeration: In our Indian System of Numeration, Commas are used to mark thousands, lakhs and crores. We use ones, tens, hundreds, thousands and then lakhs and crores. The first comma comes after hundreds place and marks thousands. The second comma comes two digits later. It comes after ten thousands place and marks lakh. The third comma comes after another two digits. It comes after ten lakh place and marks crore.

Important Questions on 6 Maths Chapter 1

Fill in the blank: 1 lakh = _______________ ten thousand.

Fill in the blank: 1 lakh = 10 ten thousand

Place commas correctly and write the numerals: Seventy-three lakh seventy-five thousand three hundred seven.

Insert commas suitable and write the names according to indian system of numeration: 87595762.

8,75,95,762 Eight crore seventy-five lakh ninety-five thousand seven hundred sixty-two.

Estimate each of the following using general rule: 730 + 998

730 round off to 700 998 round off to 1000 Estimated sum 1700

Estimate the following product using general rule: 578 x 161

578 x 161 578 round off to 600 161 round off to 200 The estimated product = 600 x 200 = 1,20,000

We are here to help you. For educational help any time you can leave a message, we will call you with in 24 hours. Our prime motive is to help the students without any delay free of cost. NCERT Books and their solutions are given in offline as well as online mode.

How many exercises, questions, and examples are there in chapter 1 of class 6th Maths?

There are 2 exercises in chapter 1 (Knowing our Numbers) of class 6th Maths. In the first exercise (Ex 1.1), there are 4 questions. Questions 1 and 2, each having five parts, and questions 3 and 4, each having four parts. In the second exercise (Ex 1.2), there are 12 word problem questions. So, there are in all 16 questions in chapter 1 (Knowing our Numbers) of class 6th Maths. There are 6 examples in chapter 1 (Knowing our Numbers), which are good for exams point of view.

What are the main topics to study in chapter 1 of class 6th Maths?

In chapter 1 of class 6th Maths, students will study:

1. Comparing Numbers.
2. How many numbers can you make?
3. Shifting digits.
4. Introducing 10,000.
5. Revisiting place value.
6. Introducing 1, 00,000.
7. Larger numbers.
8. An aid in reading and writing large numbers.
9. Use of commas.
10. Large Numbers in Practice.

Is chapter 1 of class 6th Maths difficult?

Chapter 1 of class 6th Maths is neither too easy nor too difficult. It lies in the middle of easy and difficult because some parts of this chapter are easy, and some are difficult. However, the difficulty level of any chapter varies from student to student. So, Chapter 1 of class 6th Maths is easy or not depends on students also. Some students find it complicated, some find it simple, and some find it in the middle of simple and difficult.

How much time, students need to do chapter 1 of class 6th Maths?

Students need a maximum of 5-6 days to do chapter 1 of class 6th Maths if they give at least 1-2 hours per day to this chapter. This time is an approximate time. This time can vary because no students have the same working speed, efficiency, capability, etc.

Class 6 Maths Chapter 1 Knowing Our Numbers Try these

Chapter 2: Whole Numbers »

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NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers PDF Download

The NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers provides detailed and explained Solutions for all Questions in the textbook. By referring to the Chapter 1 Knowing Our Numbers answers, students can understand each and every step; accordingly can form their own strategies to solve Questions in a proper and systematic way during further preparations.

NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers PDF

The NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers PDF prove to be worthy as it provides a lot of Questions to solve; accordingly they can score well. Students can access the Chapter 1 Knowing Our Numbers Questions of Class 6 Maths through the Selfstudys website from their comfort zone. In the process of solving Chapter 1 Knowing Our Numbers Questions, students can build a strong and solid foundation for the chapter.

Where can Students Find the NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers?

Students can find the NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers from the Selfstudys website; steps to download are clearly explained:

Visit the Selfstudys website.

NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers, NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers PDF, Download NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers PDF, NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers Revision, NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers Theory

Bring the arrow towards the NCERT Books & Solutions which can be clearly seen in the navigation bar.

Automatically a drop menu will appear, select NCERT Solutions from the list.

A new page will appear, select Class 6th from the list of classes.
Now click Maths from the list of subjects and select Chapter 1 Knowing Our Numbers from the list of chapters.

Characteristics of NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers PDF

The characteristics of NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers PDF is the distinctive quality which each and every student needs to know; some of the important features are discussed below:

All the Exercises are Covered: In the NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers revision, all the exercises of the textbook are covered so that students can get an idea about how to solve Questions.
Pictorial Representation is Given: Pictorial representations are often represented as icons, symbols, pictures, etc; these pictorial representations are given in the NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers theory.
Formulas are Included: Formula is a group of signs, letters or numbers that are used to solve Chapter 1 Knowing Our Numbers Questions; these formulas are included in the Class 6 Maths NCERT Solutions.
All Topics are Covered: In the Class 6 NCERT Maths Solutions, all the topics of Chapter 1 Knowing Our Numbers are covered so that students can have a deep understanding of the concepts.
Available in the PDF: Students can easily access the Maths Chapter 1 Knowing Our Numbers Questions from the Class 6 NCERT Solutions as it is available in portable document format.
Step By Step Approach: The Questions of Chapter 1 Knowing Our Numbers in the Class 6 Maths NCERT Solutions are solved in a step by step approach so that students can understand each and every step.

How Can NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers Help Students?

The NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers can help in several ways; those ways are discussed below:

Focuses on Fundamental Concepts: The Questions in the NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers focuses on fundamental concepts; so by solving and referring to it students can have crystal clear knowledge about the concepts.
Improves Problem Solving Skills: Problem solving skills helps students determine the source of Chapter 1 Knowing Our Numbers Questions and to find an effective solution; to improve problem solving skills, students can refer to the NCERT Class 6 Maths Solutions.
Helps in Better Grades: By using the Class 6 Maths NCERT Solutions of Chapter 1 Knowing Our Numbers, students can develop their understanding of concepts and accordingly they can improve their grades.
Explained in a Simple Language: The Chapter 1 Knowing Our Numbers Questions of NCERT Class 6 Solutions are explained in a simple language so that students can understand a lot of complex Questions easily.
Designed According to the Exam Pattern: It is believed that the Chapter 1 Knowing Our Numbers Questions from the NCERT Class 6 Maths Solutions are designed according to the latest exam pattern.
Saves Time: The Chapter 1 Knowing Our Numbers Questions of Class 6 Maths NCERT Solutions are available ready made which saves most of time; otherwise students would be wasting precious time in searching for answers.

A Comprehensive Guide to Solve Questions from NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers PDF

To solve Questions from the NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers PDF in a comprehensive way, students need to follow the given steps; those steps are:

Read the Question Carefully: Before attempting the Questions from the NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers, students need to read the question carefully so that they can understand what is being asked.
Understand the Concepts: Students should make sure that they need to understand Chapter 1 Knowing Our Numbers concepts which are related to Questions; then only they can solve Questions from the NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers revision.
Use the Formula or Method: Depending upon the types of Questions in the NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers theory, students need to use the required formula and method; through this students can score well.
Look for Clues in the Questions: Students are advised to look for clues in the Chapter 1 Knowing Our Numbers Questions in the NCERT Class 6 Maths Solutions so that they can conclude the answers.
Check the Answers: After solving the Class 6 Maths Chapter 1 Knowing Our Numbers Questions from the NCERT Solutions, students need to check the answers with their own answers then they can get an idea about the mistakes.
Set Some Goals: To solve Chapter 1 Knowing Our Numbers Questions from the NCERT Class 6 Maths Solutions, students need to set some goals rather than just thinking to complete the Questions.

How to Improve Confidence With the Help of NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers?

To improve confidence during the preparations, students can refer to the NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers; some of the scenarios to improve confidence are discussed below:

Questions are Based on the Textbook: The Questions in the NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers revision are based on the textbook. So by solving Chapter 1 Knowing Our Numbers Questions, students can gain confidence and score well in the test.
Enhances the Basic Knowledge: Once students start solving Questions from the NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers theory it can enhance the basic knowledge and improve their confidence; which can be implemented while attempting the final exams.
Covers the Difficult Topics: It is obvious that the NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers PDF covers difficult and complex topics; so by solving these Questions students can have a better understanding of concepts; accordingly they can improve their confidence level.
Students Will Learn How to Answer Questions: By solving Chapter 1 Knowing Our Numbers Questions from the NCERT Solutions of Class 6 Maths, students can learn to have different and creative approaches; this can help students to improve their confidence level.
Are Great for Revision: The NCERT Class 6 Maths Solutions of Chapter 1 Knowing Our Numbers are great for revising all topics and concepts; automatically they can improve their confidence level.
Provide Accurate Answers: The answers of Chapter 1 Knowing Our Numbers Questions of NCERT Class 6 Maths Solutions are accurate so by referring to it; students can improve their confidence level.

What are the Difficulties Faced While Solving Questions from the NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers PDF?

Students may face difficulty while solving Questions from the NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers PDF; some of the difficulties are discussed below:

Lack of Understanding of the Concepts: If in case, students don’t have an understanding for the concepts; then they may face difficulty while solving Questions from the NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers.
Difficulty in Calculations: If students are struggling with basic calculations then they can also face the same difficulty while solving Questions from the NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers revision.
Confusions With the Formulas: If in case students are not familiar with the usage of right formulas and right method, then they can face difficulty in attempting Questions from the NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers PDF.
Misreading of the Question: Students may face difficulty in solving Chapter 1 Knowing Our Numbers Questions from the NCERT Class 6 Maths Solutions if they have misunderstood the question or misinterpreted it.
Fear of Failure: It is obvious that students may be afraid of making mistakes; for them it may be very difficult in solving Chapter 1 Knowing Our Numbers Questions from the NCERT Class 6 Maths Solutions. This fear can lead to anxiety and stress level, this can be eliminated by completing the Class 6 Maths Chapter 1 Knowing Our Numbers concepts in a proper way.
Lack of Organisation: Students may face difficulty in solving Chapter 1 Knowing Our Numbers Questions from the NCERT Class 6 Maths Solutions if they are not organised in a proper way.

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Case Study Questions for Class 6 Maths

Last modified on: 7 months ago
Reading Time: 7 Minutes

Table of Contents

Here in this article, we are providing case study questions for class 6 maths.

Maths Class 6 Chapter List

Latest chapter list (2023-24).

Chapter 1 Knowing Our Numbers Case Study Questions Chapter 2 Whole Numbers Case Study Questions Chapter 3 Playing with Numbers Case Study Questions Chapter 4 Basic Geometrical Ideas Case Study Questions Chapter 5 Understanding Elementary Shape Case Study Questions Chapter 6 Integers Case Study Questions Chapter 7 Fractions Case Study Questions Chapter 8 Decimals Case Study Questions Chapter 9 Data Handling Case Study Questions Chapter 10 Mensuration Case Study Questions Chapter 11 Algebra Case Study Questions Chapter 12 Ratio and Proportion Case Study Questions

Old Chapter List

Chapter 1 Knowing Our Numbers Chapter 2 Whole Numbers Chapter 3 Playing with Numbers Chapter 4 Basic Geometrical Ideas Chapter 5 Understanding Elementary Shape Chapter 6 Integers Chapter 7 Fractions Chapter 8 Decimals Chapter 9 Data Handling Chapter 10 Mensuration Chapter 11 Algebra Chapter 12 Ratio and Proportion Chapter 13 Symmetry Chapter 14 Practical Geometry

Deleted Chapter:

Tips for Answering Case Study Questions for Class 6 Maths in Exam

1. Comprehensive Reading for Context: Prioritize a thorough understanding of the provided case study. Absorb the contextual details and data meticulously to establish a strong foundation for your solution.

2. Relevance Identification: Pinpoint pertinent mathematical concepts applicable to the case study. By doing so, you can streamline your thinking process and apply appropriate methods with precision.

3. Deconstruction of the Problem: Break down the complex problem into manageable components or steps. This approach enhances clarity and facilitates organized problem-solving.

4. Highlighting Key Data: Emphasize critical information and data supplied within the case study. This practice aids quick referencing during the problem-solving process.

5. Application of Formulas: Leverage pertinent mathematical formulas, theorems, and principles to solve the case study. Accuracy in formula selection and unit usage is paramount.

6. Transparent Workflow Display: Document your solution with transparency, showcasing intermediate calculations and steps taken. This not only helps track progress but also offers insight into your analytical process.

7. Variable Labeling and Definition: For introduced variables or unknowns, offer clear labels and definitions. This eliminates ambiguity and reinforces a structured solution approach.

8. Step Explanation: Accompany each step with an explanatory note. This reinforces your grasp of concepts and demonstrates effective application.

9. Realistic Application: When the case study pertains to real-world scenarios, infuse practical reasoning and logic into your solution. This ensures alignment with real-life implications.

10. Thorough Answer Review: Post-solving, meticulously review your answer for accuracy and coherence. Assess its compatibility with the case study’s context.

11. Solution Recap: Before submission, revisit your solution to guarantee comprehensive coverage of the problem and a well-organized response.

12. Previous Case Study Practice: Boost your confidence by practicing with past case study questions from exams or textbooks. This familiarity enhances your readiness for the question format.

13. Efficient Time Management: Strategically allocate time for each case study question based on its complexity and the overall exam duration.

14. Maintain Composure and Confidence: Approach questions with poise and self-assurance. Your preparation equips you to conquer the challenges presented.

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NCERT Exemplar
NCERT Exemplar Class 6
Class 6 Maths
Chapter 1 Number System

NCERT Exemplar Solutions for Class 6 Maths Chapter 1 Number System

NCERT Exemplar Solutions for Class 6 Maths Chapter 1 Number System are given here in a simple but comprehensive way. These solutions are extremely helpful for students to clear all their doubts easily and understand the basics of the chapter more effectively. It is essential to understand the various kinds of questions and figure out the best answers for them. Hence, students who wish to score good marks in Maths can practise NCERT Exemplar Solutions for Class 6 Maths .

NCERT Exemplar Solutions for Class 6 Maths Chapter 1 Number System are available for free download in PDF, which contains solutions to all the questions provided in the exemplar book. A system for representing or expressing numbers of a certain type is known as the number system. Now, let us have a look at some of the concepts discussed in this chapter.

Reading and writing of large numbers
Comparing large numbers
Indian system of numeration
International system of numeration
Roman numerals
Natural numbers
Predecessor and successor of a natural number
Representation of whole numbers on the number line
Addition and subtraction of whole numbers on the number
Properties of whole numbers
Factors and multiples
Number of factors of a given number is finite
Number of multiples of a given number is infinite
Perfect number
Prime factorisation of a number:
Highest Common Factor (HCF) of two or more numbers
Least Common Multiple (LCM) of two or more numbers

Download the PDF of NCERT Exemplar Solutions for Class 6 Maths Chapter 1 Number System

ncert exemplar class 6 maths sol ch 1 01

Access Answers to NCERT Exemplar Solutions for Class 6 Maths Chapter 1 Number System

Exercise Page: 5

In questions 1 to 38, out of the four options, only one is correct. Write the correct answer.

1. The product of the place values of two 2’s in 428721 is

(A) 4 (B) 40000 (C) 400000 (D) 40000000

The product of the place values of two 2’s in 428721 is

There are two 2’s in the given number.

So, the first 2 are in the tenth place,

Then, the product is = 2 × 10

The other 2 is in place value of ten thousand.

Then, = 2 × 10000

Therefore, the product of place values = 20 × 20000

2. 3 × 10000 + 7 × 1000 + 9 × 100 + 0 ×10 + 4 is the same as

(A) 3794 (B) 37940 (C) 37904 (D) 379409

3 × 10000 = 30000

The place value is 30000

7 × 1000 = 7000

The place value is 7000

9 × 100 = 900

The place value is 900

Therefore, the sum of all place value is = 30000 + 7000 + 900 + 0 + 4

3. If 1 is added to the greatest 7- digit number, it will be equal to

(A) 10 thousand (B) 1 lakh (C) 10 lakh (D) 1 crore

Solution: –

(D) 1 crore

We know that, the greatest number is 99,99,999

Then, 1 is added to 99,99,999 = 99,99,999 + 1

= 1,00,00,000

4. The expanded form of the number 9578 is

(A) 9 × 10000 + 5 × 1000 + 7 × 10 + 8 × 1

(B) 9 × 1000 + 5 × 100 + 7 × 10 + 8 × 1

(D) 9 × 100 + 5 × 100 + 7 × 10 + 8 × 1

Consider the given number 9578,

The place value of 8 is ones = 8 × 1

The place value of 7 is tens = 7 × 10

The place value of 5 is thousand = 5 × 100

The place value of 9 is ten thousand = 9 × 1000

5. When rounded off to nearest thousands, the number 85642 is

(A) 85600 (B) 85700 (C) 85000 (D) 86000

When rounded off to nearest thousands, the number 85642 is = 86000

6. The largest 4-digit number, using any one digit twice, from digits 5, 9, 2 and 6 is

(A) 9652 (B) 9562 (C) 9659 (D) 9965

Using 9 as twice from 5, 9, 2 and 6, then the number is 9965.

7. In the Indian System of Numeration, the number 58695376 is written as

(A) 58,69, 53, 76 (B) 58,695,376

In Indian System of Numeration, the number 58695376 is written as 5 crore, eighty six lakh, ninety five thousand, three hundred and seventy six = 5,86,95,376

8. One million is equal to

(A) 1 lakh (B) 10 lakh (C) 1 crore (D) 10 crore

(B) 10 Lakh

One million is equal to ten lakhs.

1,000,000 = 10,00,000

9. The greatest number, which on rounding off to nearest thousands, gives 5000, is

(A) 5001 (B) 5559 (C) 5999 (D) 5499

The greatest number which on rounding off to nearest thousands gives 5000, is 5499.

10. Keeping the place of 6 in the number 6350947 same, the smallest number obtained by rearranging other digits is

(A) 6975430 (B) 6043579 (C) 6034579 (D) 6034759

Keeping the place of 6 in the number 6350947 same, the smallest number obtained by rearranging other digits is 6034579.

11. Which of the following numbers in Roman numerals is incorrect?

(A) LXXX (B) LXX (C) LX (D) LLX

As we know that, the symbol L can never be repeated.

Therefore, LLX is incorrect.

12. The largest 5-digit number having three different digits is

(A) 98978 (B) 99897 (C) 99987 (D) 98799

In the given, options there are three numbers used 9, 8 and 7

To get the largest of 5- digit we have to arrange the numbers in descending order.

Then, from the given options 99987 is the largest of 5 – digit number.

13. The smallest 4-digit number having three different digits is

(A) 1102 (B) 1012 (C) 1020 (D) 1002

In the given, options there are three numbers used 0, 1 and 2

To get the largest of 4- digit we have to arrange the numbers in ascending order.

Then, from the given options 1002 is the smallest of 4 – digit number.

14. Number of whole numbers between 38 and 68 is

(A) 31 (B) 30 (C) 29 (D) 28

Number of whole numbers between 38 and 68 is 29.

15. The product of successor and predecessor of 999 is

(A) 999000 (B) 998000 (C) 989000 (D) 1998

The number which comes immediately before a particular number is called its predecessor.

The successor of a whole number is the number obtained by adding 1 to it.

So, Successor of 999 = 999 + 1 = 1000

Predecessor = 999 – 1 = 998

Then, product of successor and predecessor of 999 is = 1000 × 998

16. The product of a non-zero whole number and its successor is always

(A) an even number (B) an odd number

(A) an even number

The product of a non-zero whole number and its successor is always an even number.

For example: – 4 × 5 = 20, 7 × 8 = 56

17. A whole number is added to 25 and the same number is subtracted from 25. The sum of the resulting numbers is

(A) 0 (B) 25 (C) 50 (D) 75

Let us assume the number be x.

From the question it is given that, number is added to 25 = x + 25

The same number is subtracted to from 25 = 25 – x

Then, the sum of the resulting numbers is = (x + 25) + (25 – x)

= x + 25 + 25 – x

= 50 + x – x

18. Which of the following is not true?

(A) (7 + 8) + 9 = 7 + (8 + 9)

(B) (7 × 8) × 9 = 7 × (8 × 9)

(D) 7 × (8 + 9) = (7 × 8) + (7 × 9)

Consider the left hand side = 7 + 8 × 9

= 7 + (8 × 9)

Now, consider the right hand side = (7 + 8) × (7 + 9)

By comparing LHS and RHS

19. By using dot (.) patterns, which of the following numbers can be arranged in all the three ways namely a line, a triangle and a rectangle?

(A) 9 (B) 10 (C) 11 (D) 12

NCERT Exemplar Class 6 Maths Solutions Chapter 1 Number System Image 1

20. Which of the following statements is not true?

(A) Both addition and multiplication are associative for whole numbers.

(B) Zero is the identity for multiplication of whole numbers.

(D) Multiplication is distributive over addition for whole numbers.

Example:- 1 × 0 = 0

21. Which of the following statements is not true?

(A) 0 + 0 = 0 (B) 0 – 0 = 0

(D) 0 ÷ 0 = 0

Zero divided by zero is not defined.

22. The predecessor of 1 lakh is

(A) 99000 (B) 99999 (C) 999999 (D) 100001

The predecessor of 1 lakh is = 1,00,000 – 1

23. The successor of 1 million is

(A) 2 millions (B) 1000001 (C) 100001 (D) 10001

(B) 1000001

We know that, 1 million = 10,00,000

Then, successor = 10,00,000 + 1

= 10,00,001

24. Number of even numbers between 58 and 80 is

(A) 10 (B) 11 (C) 12 (D) 13

Even numbers between 58 and 80 are 60, 62, 64, 66, 68, 70, 72, 74, 76, 78.

25. Sum of the number of primes between 16 to 80 and 90 to 100 is

(A) 20 (B) 18 (C) 17 (D) 16

Prime numbers between 16 to 80 = 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73 and 79.

Then, number of primes between 16 to 80 = 16

Prime numbers between 90 to 100 = 97

Then, number of primes between 90 to 100 = 1

Therefore, Sum of the number of primes between 16 to 80 and 90 to 100 is,

26. Which of the following statements is not true?

(A) The HCF of two distinct prime numbers is 1

(B) The HCF of two co-prime numbers is 1

(D) The HCF of an even and an odd number is even.

The HCF of an even and an odd number is odd number.

27. The number of distinct prime factors of the largest 4-digit number is

(A) 2 (B) 3 (C) 5 (D) 11

The largest 4 – digit number = 9999

Prime factors of 9999 = 3 × 3 × 11 × 101

So, 9999 = 3 2 × 11 × 101

Therefore, distinct prime factors are = 3, 11 and 101

Number of distinct prime factors of the largest 4-digit number is = 3

28. The number of distinct prime factors of the smallest 5-digit number is

(A) 2 (B) 4 (C) 6 (D) 8

The smallest 5 – digit number = 10000

Prime factors of 10000 = 2 × 2 × 2 × 2 × 5 × 5 × 5 × 5

So, 10000 = 2 4 × 5 4

Therefore, distinct prime factors are = 2 and 5

Number of distinct prime factors of the smallest 5-digit number is = 2

29. If the number 7254*98 is divisible by 22, the digit at * is

(A) 1 (B) 2 (C) 6 (D) 0

Take the alternating sum of the digits in the number, read from left to right. If that is divisible by 11, then the original number.

7 – 2 + 5 – 4 + * – 9 + 8 = (5 + *)

For the given number 7254 * 98 to be divisible by 11,

(5 + *) must also be divisible by 11

So, 5 + * = 11

Therefore * = 11 – 5

30. The largest number which always divides the sum of any pair of consecutive odd numbers is

1 + 3 = 4 = 4/4 = 1

3 + 5 = 8 = 8/4 = 2

The largest number which always divides the sum of any pair of consecutive odd numbers is 4.

31. A number is divisible by 5 and 6. It may not be divisible by

(A) 10 (B) 15 (C) 30 (D) 60

The LCM of 6 and 5 is 30.

So, 30 is divisible by 10, 15 and 30 in the given options.

But, 30 is not divisible by 60.

32. The sum of the prime factors of 1729 is

(A) 13 (B) 19 (C) 32 (D) 39

The prime factors of 1729 = 7 × 13 × 19

Therefore, the sum of prime numbers = 7 + 13 + 19

33. The greatest number which always divides the product of the predecessor and successor of an odd natural number other than 1, is

(A) 6 (B) 4 (C) 16 (D) 8

Let us assume an odd natural number be 5.

Then, predecessor of 5 = 5 -1 = 4

Successor of 5 = 5 + 1 = 6

Then, the product of predecessor and successor = 4 × 6

24 is divided by 4 = 24/4 = 6

Therefore, the greatest number which always divides the product of the predecessor and successor of an odd natural number other than 1, is 4.

34. The number of common prime factors of 75, 60, 105 is

(A) 2 (B) 3 (C) 4 (D) 5

Prime factors of,

75 = 3 × 5 × 5

60 = 2 × 2 × 3 × 5

105 = 3 × 5 × 7

So, common prime factors in the given three numbers are 3 and 5.

Therefore, the number of common prime factors of 75, 60, 105 is 2.

35. Which of the following pairs is not coprime?

(A) 8, 10 (B) 11, 12 (C) 1, 3 (D) 31, 33

First of all, both the numbers are even.

Then, common factor of both numbers is 2 other than 1.

Therefore, 8 and 10 are not coprime.

36. Which of the following numbers is divisible by 11?

(A) 1011011 (B) 1111111 (C) 22222222 (D) 3333333

To check the divisibility of a number by 11, the rule is to find the difference between the sum of the digits at odd places (from the right) and the sum of the digits at even places (from the right) of the number. If the difference is either 0 or divisible by 11, then the number is divisible by 11.

So, 2 – 2 + 2 – 2 + 2 – 2 + 2 – 2 = 0

Therefore, 22222222 is divisible by 11.

37. LCM of 10, 15 and 20 is

(A) 30 (B) 60 (C) 90 (D) 180

Factors of 10, 15 and 30 is,

NCERT Exemplar Class 6 Maths Solutions Chapter 1 Number System Image 2

Then, LCM of 10, 15 and 30 is 2 × 2 × 3 × 5 × 1 = 60

38. LCM of two numbers is 180. Then which of the following is not the HCF of the numbers?

(A) 45 (B) 60 (C) 75 (D) 90

Factors of 180.

NCERT Exemplar Class 6 Maths Solutions Chapter 1 Number System Image 3

Then, factors of 180 = 2 × 2 × 3 × 3 × 5

180 is not divided by 180.

Therefore, 75 is not the HCF of the number 180.

In questions 39 to 98, state whether the given statements are true (T) or false (F).

39. In Roman numeration, a symbol is not repeated more than three times.

As per the rule of the Roman numerals, a symbol is not repeated more than three times.

40. In Roman numeration, if a symbol is repeated, its value is multiplied as many times as it occurs.

If a symbol is repeated, its value is added as many times as it occurs: i.e. II is equal 2, XX is 20 and XXX is 30.

41. 5555 = 5 × 1000 + 5 × 100 + 5 × 10 + 5 × 1

Left Hand Side = 5555

Right Hand Side = 5 × 1000 + 5 × 100 + 5 × 10 + 5 × 1

= 5000 + 500 + 50 + 5

Left Hand Side = Right Hand Side

42. 39746 = 3 × 10000 + 9 × 1000 + 7 × 100 + 4 × 10 + 6

Left Hand Side = 39746

Right Hand Side = 3 × 10000 + 9 × 1000 + 7 × 100 + 4 × 10 + 6

= 30000 + 9000 + 700 + 40 + 6

43. 82546 = 8 × 1000 + 2 × 1000 + 5 × 100 + 4 × 10 + 6

Left Hand Side = 82546

Right Hand Side = 8 × 1000 + 2 × 1000 + 5 × 100 + 4 × 10 + 6

= 8000 + 2000 + 500 + 40 + 6

Left Hand Side ≠ Right Hand Side

44. 532235 = 5 × 100000 + 3 × 10000 + 2 × 1000 + 2 × 100 + 3 × 10 + 5

Left Hand Side = 532235

Right Hand Side = 5 × 100000 + 3 × 10000 + 2 × 1000 + 2 × 100 + 3 × 10 + 5

= 5,00,000 + 30,000 + 2000 + 200 + 30 + 5

45. XXIX = 31

Where, X = 10

So, XXIX = 10 + 10 + 9

46. LXXIV = 74

Where, L = 50

So, LXXIV = 50 + 10 + 10 + 4

47. The number LIV is greater than LVI.

So, LIV = 50 + 4 = 54

LVI = 50 + 6

Therefore, 54 < 56

Hence, LIV < LVI

48. The numbers 4578, 4587, 5478, 5487 are in descending order.

In the question, the arrangement of the numbers in ascending order.

Descending order of the given number = 5487, 5478, 4587, 4578.

49. The number 85764 rounded off to nearest hundreds is written as 85700.

The number 85764 rounded off to nearest hundreds is written as 85800.

50. Estimated sum of 7826 and 12469 rounded off to hundreds is 20,000.

The number 7826 rounded off to nearest hundreds is written as 7800.

The number 12469 rounded off to nearest hundreds is written as 12500

So, sum of numbers after rounded off to hundreds = 7800 + 12500 = 20,300

Therefore, 20,300 is nearest to 20,000.

51. The largest six digit telephone number that can be formed by using digits 5, 3, 4, 7, 0, 8 only once is 875403.

The largest six digit telephone number that can be formed by using digits 5, 3, 4, 7, 0, 8 only once is 875430.

52. The number 81652318 will be read as eighty one crore six lakh fifty two thousand three hundred eighteen.

The given number 8,16,52,318 will be read as eight crore sixteen lakh fifty two thousand three hundred and eighteen.

53. The largest 4-digit number formed by the digits 6, 7, 0, 9 using each digit only once is 9760.

54. Among kilo, milli and centi, the smallest is centi.

Among kilo, milli and centi, the smallest is milli.

55. Successor of a one-digit number is always a one-digit number.

Example: – consider the number 9 it is a one digit, then its successor = 9 + 1 = 10.

56. Successor of a 3-digit number is always a 3-digit number.

Example: – consider 3-digit number 999 it is a one digit, then its successor = 999 + 1 = 1000.

57. Predecessor of a two-digit number is always a two-digit number.

Example: – consider 2-digit number 10, then its predecessor = 10 – 1 = 9.

58. Every whole number has its successor.

59. Every whole number has its predecessor.

Consider the whole number 0,

Then, its predecessor = 0 – 1 = -1

– 1 is an integer.

60. Between any two natural numbers, there is one natural number.

Consider the two natural numbers 4 and 8.

Then, natural numbers between 4 and 8 are 5, 6, 7.

61. The smallest 4-digit number is the successor of the largest 3-digit number.

The largest 3-digit number = 999

Then, its successor = 999 + 1

62. Of the given two natural numbers, the one having more digits is greater.

As per the rule, Of the given two natural numbers, the one having more digits is greater.

63. Natural numbers are closed under addition.

We know that, sum of two natural numbers is always natural number.

Therefore, natural numbers are closed under addition.

64. Natural numbers are not closed under multiplication.

We know that, multiplication of two natural numbers is always natural number.

Therefore, natural numbers are closed under multiplication.

65. Natural numbers are closed under subtraction.

Difference of two natural numbers are not always a natural number.

Therefore, natural numbers are not closed under subtraction.

66. Addition is commutative for natural numbers.

Let us assume ‘a’ and ‘b’ are the two natural numbers.

Then commutative for natural numbers is a + b = b + a.

Consider the two natural numbers 2 and 4.

Where, a = 2, b = 4

a + b = b + a

2 + 4 = 4 + 2

67. 1 is the identity for addition of whole numbers.

Zero (0) is the identity for addition of whole numbers.

Consider any whole number i.e. 8.

Then, 8 + 0 = 8

68. 1 is the identity for multiplication of whole numbers.

Consider any whole number i.e. 6.

69. There is a whole number which when added to a whole number, gives the number itself.

Zero (0) is a whole number which when added to a whole number, gives the number itself.

70. There is a natural number which when added to a natural number, gives the number itself.

We know that, ‘0’ is not a natural number.

Therefore, there is no any natural number which when added to a natural number, gives the number itself.

71. If a whole number is divided by another whole number, which is greater than the first one, the quotient is not equal to zero.

As per the standard rule, if a whole number is divided by another whole number, which is greater than the first one, the quotient is not equal to zero.

72. Any non-zero whole number divided by itself gives the quotient 1.

Consider any non-zero whole number i.e. 5

5 is divided by itself = 5/5 = 1

73. The product of two whole numbers need not be a whole number.

The product of two whole number is always a whole number.

Because, we know that, whole numbers are closed under multiplication.

74. A whole number divided by another whole number greater than 1 never gives the quotient equal to the former.

As per the standard rule, a whole number divided by another whole number greater than 1 never gives the quotient equal to the former.

75. Every multiple of a number is greater than or equal to the number.

As per the standard rule, every multiple of a number is greater than or equal to the number.

76. The number of multiples of a given number is finite.

The number of multiples of a given number is infinite.

Because, we know that numbers are infinite.

77. Every number is a multiple of itself.

We know that, 1 is the identity for multiplication of whole numbers

Therefore, any number is multiplied by 1 we get the number itself.

Hence, every number is a multiple of itself.

78. Sum of two consecutive odd numbers is always divisible by 4.

For example, 1 + 3 = 4 = 4/4 = 1

11 + 13 = 24 = 24/4 = 6

79. If a number divides three numbers exactly, it must divide their sum exactly.

As per the standard rule, if a number divides three numbers exactly, it must divide their sum exactly.

Let us consider one number i.e. 2, it divides 4, 6 and 8.

Then, sum of three numbers = 4 + 6 + 8

= 18 is exactly divisible by 2

80. If a number exactly divides the sum of three numbers, it must exactly divide the numbers separately.

81. If a number is divisible both by 2 and 3, then it is divisible by 12.

Let us consider the number 6, it is actually divisible by 2 and 3, But 6 is not divisible by 12.

82. A number with three or more digits is divisible by 6, if the number formed by its last two digits (i.e., ones and tens) is divisible by 6.

83. A number with 4 or more digits is divisible by 8, if the number formed by the last three digits is divisible by 8.

As per the rule of divisibility test, a number with 4 or more digits is divisible by 8, if the number formed by the last three digits is divisible by 8.

84. If the sum of the digits of a number is divisible by 3, then the number itself is divisible by 9.

As per the rule of divisibility test, the sum of the digits of a number is divisible by 9, then the number itself is divisible by 9.

85. All numbers which are divisible by 4 may not be divisible by 8.

Consider the number 20, it is divisible by 4 but not divisible by 8.

86. The Highest Common Factor of two or more numbers is greater than their Lowest Common Multiple.

The Highest Common Factor of two or more numbers is lower than their Lowest Common Multiple.

87. LCM of two or more numbers is divisible by their HCF.

As per the rule, LCM of two or more numbers is divisible by their HCF.

88. LCM of two numbers is 28 and their HCF is 8.

From the question it is given that, LCM of two numbers is 28 and their HCF is 8.

But, 28 is not exactly divided by 8.

89. LCM of two or more numbers may be one of the numbers.

Consider the two numbers 2 and 4.

Then, LCM of 2 and 4 is 4.

90. HCF of two or more numbers may be one of the numbers.

91. Every whole number is the successor of another whole number.

We know that, 0 is the whole number.

0 is no the successor of another whole number.

92. Sum of two whole numbers is always less than their product.

For example:-

From the above example, we can say that s um of two whole numbers is not always less than their product.

93. If the sum of two distinct whole numbers is odd, then their difference also must be odd.

Consider the two odd numbers 2 and 5.

Then, sum = 2 + 5 = 7 it is an odd number.

Now, difference = 2 – 5 = 3 it also an odd number.

94. Any two consecutive numbers are coprime.

Co-prime number is a set of numbers or integers which have only 1 as their common factor i.e. their highest common factor (HCF) will be 1. Co-prime numbers are also known as relatively prime or mutually prime numbers. It is important that there should be two numbers in order to form co-primes.

95. If the HCF of two numbers is one of the numbers, then their LCM is the other number.

96. The HCF of two numbers is smaller than the smaller of the numbers.

The HCF of two numbers is either greater than or equal to the smaller of the numbers.

97. The LCM of two numbers is greater than the larger of the numbers.

The LCM of two numbers may be equal to or greater than the larger of the numbers.

98. The LCM of two coprime numbers is equal to the product of the numbers.

In questions 99 to 151, fill in the blanks to make the statements true.

99. (a) 10 million = _____ crore.

10 million = 1 crore

We know that, 1 million = 10 lakh

Then, 10 million = 10 × 10 = 100 lakh = 1,00,00,000

Therefore, 10 million = 1 crore.

(b) 10 lakh = _____ million.

10 lakh = 1 million.

100. (a) 1 metre = _____ millimetres.

1 metre = 1000millimetres

We know that, 1 metre = 100 centimetre

1 centimetre = 10 millimeter

Then, 100 cm = 10 × 100 = 1000 millimetres

(b) 1 centimetre = _____ millimetres.

1 centimetre = 10 millimetres.

1 kilometre = 10,00,000 millimetres.

We know that, 1 km = 1000 meters.

1 metre = 100 centimetre

1000 metre = 1000 × 100

= 1,00,000 centimetre

1 cm = 10 millimetres

Then, 1,00,000 centimetre = 10 × 1,00,000 = 10,00,000 millimetres

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CBSE Class 10 Study Material

CBSE Class 10 Maths Case Study Questions for Class 10 Maths Chapter 1 - Real Numbers (Published by CBSE)

Cbse class 10 maths cased study question bank for chapter 1 - real numbers is available here. this question bank is very useful to prepare for the class 10 maths exam 2021-2022..

The Central Board of Secondary Education has introduced the case study questions in class 10 exam pattern 2021-2022. The CBSE Class 10 questions papers of Board Exam 2022 will have questions based on case study. Therefore, students should get familiarised with these questions to do well in their board exam.

We have provided here case study questions for Class 10 Maths Chapter 1 - Real Numbers. These questions have been published by the CBSE board itself. Students must solve all these questions at the same time they finish with the chapter - Real numbers.

Case Study Questions for Class 10 Maths Chapter 1 - Real Numbers

To enhance the reading skills of grade X students, the school nominates you and two of your friends to set up a class library. There are two sections- section A and section B of grade X. There are 32 students in section A and 36 students in section B.

1. What is the minimum number of books you will acquire for the class library, so that they can be distributed equally among students of Section A or Section B?

Answer: c) 288

2. If the product of two positive integers is equal to the product of their HCF and LCM is true then, the HCF (32 , 36) is

Answer: b) 4

3. 36 can be expressed as a product of its primes as

a) 2 2 × 3 2

b) 2 1 × 3 3

c) 2 3 × 3 1

d) 2 0 × 3 0

Answer: a) 2 2 × 3 2

4. 7 × 11 × 13 × 15 + 15 is a

a) Prime number

b) Composite number

c) Neither prime nor composite

d) None of the above

Answer: b) Composite number

5. If p and q are positive integers such that p = ab 2 and q= a 2 b, where a , b are prime numbers, then the LCM (p, q) is

Answer: b) a 2 b 2

CASE STUDY 2:

A seminar is being conducted by an Educational Organisation, where the participants will be educators of different subjects. The number of participants in Hindi, English and Mathematics are 60, 84 and 108 respectively.

1. In each room the same number of participants are to be seated and all of them being in the same subject, hence maximum number participants that can accommodated in each room are

Answer: b) 12

2. What is the minimum number of rooms required during the event?

Answer: d) 21

3. The LCM of 60, 84 and 108 is

Answer: a) 3780

4. The product of HCF and LCM of 60,84 and 108 is

Answer: d) 45360

5. 108 can be expressed as a product of its primes as

a) 2 3 × 3 2

b) 2 3 × 3 3

c) 2 2 × 3 2

d) 2 2 × 3 3

Answer: d) 2 2 × 3 3

CASE STUDY 3:

A Mathematics Exhibition is being conducted in your School and one of your friends is making a model of a factor tree. He has some difficulty and asks for your help in completing a quiz for the audience.

Observe the following factor tree and answer the following:

1. What will be the value of x?

Answer: b) 13915

2. What will be the value of y?

Answer: c) 11

3. What will be the value of z?

Answer: b) 23

4. According to Fundamental Theorem of Arithmetic 13915 is a

a) Composite number

b) Prime number

d) Even number

Answer: a) Composite number

5. The prime factorisation of 13915 is

a) 5 × 11 3 × 13 2

b) 5 × 11 3 × 23 2

c) 5 × 11 2 × 23

d) 5 × 11 2 × 13 2

Answer: c) 5 × 11 2 × 23

Also Check:

CBSE Case Study Questions for Class 10 Maths - All Chapters

Tips to Solve Case Study Based Questions Accurately

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Class 6 Maths Exercise 1.1 Chapter 1 Knowing Your Numbers Solutions

NCERT Solutions Class 6 Maths Chapter 1 Knowing Your Numbers Exercise 1.1 are provided here. These solutions are prepared by expert teachers to guide you in your exam preparation. The solutions are always prepared by following NCERT guidelines, so that it covers the whole syllabus accordingly. Our CBSE Class 6 Maths Solutions Chapter 1 Exercise 1.1 Solutions are very helpful in scoring well in examinations.

NCERT Solutions for Class 6 Maths Chapter 1 Exercise 1.1

EXERCISE: 1.1

Question 1: Fill in the blanks:

(a) 1 lakh = ………….. ten thousand. (b) 1 million = ………… hundred thousand. (c) 1 crore = ………… ten lakh. (d) 1 crore = ………… million. (e) 1 million = ………… lakh.

Answer: (a) 10 (b) 10 (c) 10 (d) 10 (e) 10

Question 2: Place commas correctly and write the numerals:

(a) Seventy-three lakh seventy-five thousand three hundred seven.

(b) Nine crore five lakh forty-one.

(d) Fifty-eight million four hundred twenty-three thousand two hundred two.

(e) Twenty-three lakh thirty thousand ten.

(a) 73,75,307 (b) 9,05,00,041 (c) 7,52,21,302 (d) 5,84,23,202 (e) 23,30,010.

Question 3: Insert commas suitable and write the names according to Indian system of numeration:

(a) 87595762 (b) 8546283 (c) 99900046 (d) 98432701

(a) 8,75,95,762

Eight crore seventy-five lakh ninety-five thousand seven hundred sixty-two.

(b) 85,46,283

Eighty-five lakh forty-six thousand two hundred eighty-three.

Nine crore ninety-nine lakh forty-six.

(d) 9,84,32,701

Nine crore eighty-four lakh thirty-two thousand seven hundred one.

Question 4: Insert commas suitable and write the names according to International system of numeration:

(a) 78921092 (b) 7452283 (c) 99985102 (d) 48049831

(a) 78,921,092

Seventy-eight million nine hundred twenty-one thousand ninety-two

(b) 7,452,483

Seven million four hundred fifty-two thousand two hundred eighty-three

Ninety-nine million nine hundred eighty-five thousand one hundred two

(d) 48,049,831

Forty-eight million forty-nine thousand eight hundred thirty-one

Access NCERT Solutions for Class 6 Maths Chapter 1 Knowing Your Numbers – All Exercises

Below we have provided the links to check solutions of the other exercises of the chapter.

NCERT Solutions for Class 6 Maths Chapter 1 (Ex 1.1)

NCERT Maths Book Class 6 Chapter 1 - Knowing your Numbers is an ideal study material for students to comprehensively understand the dynamics of mathematics. Students can download NCERT solution PDF for the latest CBSE NCERT Books for Class 6 Maths online from Vedantu that come with step by step techniques to solve problems. The NCERT Class 6 Maths PDF is designed with compliance to the latest CBSE curriculum. Download NCERT Solutions PDF for exam preparation via their mock tests. Subjects like Science, Maths, English,Hindi will become easy to study if you have access to NCERT Solution for Class 6 Science, Maths solutions and solutions of other subjects.

Access NCERT Solutions for Class 6 Maths Chapter 1-Knowing Our Numbers

1. Fill in the blanks:

(a) $1$Lakh in terms of ten thousand?

Ans: $1$ lakh is $10$ ten thousand

(b) $1$ Million in terms of hundred thousand

Ans: $1$ million is $10$ hundred thousand

Ans: $1$ crore is $10$ ten lakh

(d) $1$ million in terms of lakh

Ans: $1$ million is $10$ lakh

2. Place commas correctly and write the numerals:

(a) Seventy three lakh seventy five thousand three hundred seven.

Ans: Seventy-three lakh seventy-five thousand three hundred seven in numerals is written as shown

$73,75,307$

(b) Nine crore five lakh forty one.

Ans: Nine crore five lakh forty-one in numerals is written as shown

$9,05,00,041$

Ans: Seven crore fifty-two lakh twenty-one thousand three hundred two in numerals is written as shown

$7,52,21,302$

(d) Fifty eight million four hundred twenty three thousand two hundred two.

Ans: Fifty-eight million four hundred twenty-three thousand two hundred two in numerals is written as shown

$58,423,202$

(e) Twenty three lakh thirty thousand ten.

Ans: Twenty-three lakh thirty thousand ten in numerals is written as shown

$23,30,010$

3. Insert commas suitably and write the names according to Indian system of numeration:

(a) $87595762$

Ans: Commas and names according to Indian system of numeration is given as shown

$8,75,95,762\to $Eight crore seventy-five lakh ninety-five thousand seven hundred sixty-two

(b) $8546283$

$85,46,283\to $Eighty-five lakh forty-six thousand two hundred eighty-three

$9,99,00,046\to $Nine crore ninety-nine lakh forty-six

(d) $98432701$

$9,84,32,701\to $Nine crore eighty-four lakh thirty-two thousand seven hundred one

4. Insert commas suitably and write the names according to International system of numeration:

(a) $78921092$

Ans: Commas and names according to International system of numeration is given as shown:

$78,921,092\to $seventy-eight million nine hundred twenty-one thousand ninety-two

(b) $7452283$

$7,452,283\to $seven million four hundred fifty-two thousand two hundred eighty-three

$99,985,102\to $Ninety-nine million nine hundred eighty five thousand one hundred two

(d) $48049831$

$48,049,831\to $Forty-eight million forty-nine thousand eight hundred thirty-one

NCERT Solutions for Class 6 Maths Chapter 1 - Exercise 1.1

The NCERT Solution for Class 6 Maths eases understanding by providing a step-by-step guide to the problems in Exercise 1.1. It allows students to understand large numbers thoroughly, which has further implications outside conventional mathematics.

The NCERT books online comprise every problem in the exercise, such as converting from international method to the Indian method or vice versa.

Here is a list of the problems included in the first exercise of Class 6 Maths Chapter 1

NCERT Maths Class 6 Exercise 1.1 Question 1

The first question is a simple Fill in the Blanks that asks students to convert numbers from the numeration method to another. The cue to the conversion will be given with the usage of varying naming systems.

For instance, 1 Lakh = ___ ten thousand.

This question segment will help students test their assessment skills of different numerical methods as well as their understanding of the same. The NCERT books PDF can be used by students to solve the problems.

NCERT Maths Class 6 Exercise 1.1 Question 2

This question assesses students’ understanding of large numbers by numerical names. It poses large numbers in words and asks students to write the numeric version of it by placing the commas. The commas should be per the Indian numeric system. For instance, nine crores five lakh forty one should be written as 9, 05, 00, 041 as the name is in the Indian system. Students can refer to the NCERT Books download for solutions.

NCERT Solutions for Class 6 Maths Exercise 1.1 Question 3

This question poses numbers without any comma splicing and asks students to put commas according to the Indian system of numeration. It also asks students to write number names as per the Indian system.

For instance, 99900046 as per given instructions should be rewritten as 9,99,00,046 and named as Nine crore ninety-nine lakh forty-six.

In case students cannot understand the method, they can look up in the NCERT books PDF for a thorough understanding of the step-by-step guide.

NCERT Solutions for Class 6 Maths Exercise 1.1 Question 4

Regarding this question, students need to put commas and rewrite the numbers according to the International numeric system. They also need to write the names of the numbers in compliance with such an International method. For example, 48049831 needs to be rewritten as 48, 049, 831, and the name for it should be Forty-eight million forty-nine thousand eight hundred and thirty-one. Students can take the help of the Class 6th Maths NCERT Solutions for a better grip on how to solve the same.

These are the types of questions that students will come across in exercise 1.1 of the CBSE NCERT Class 6 Maths textbook. Students can also look for solutions to other exercises in the PDF provided by Vedantu.

NCERT Maths Book Class 6 Chapter 1 Knowing your Numbers – An Overview

The NCERT Class 6 Maths solution from Vedantu allows students to develop a keen analytical sense, reasoning power, and problem-solving ability. It also leaves room for culturing creative and critical thinking in young minds.

The NCERT Solution for Class 6 Maths is devised in a fashion that will hone their mathematical skills and prepare them for future endeavors. In the case of the chapter in discussion - it is the introductory chapter of Class 6.

NCERT Maths Book Class 6 Chapter 1 Solutions deals with the basic mathematical component of large numbers. In this chapter, students will learn about large numbers up to 1 Crore. This chapter begins with methods of numeration used internationally as well as in India.

It will also have information regarding Roman numerals and the estimation of large numbers. It will allow students to comprehend large numbers and name them according to international and Indian methods.

Our solutions offer shortcut techniques for easier understanding. The procedures used in CBSE 6th Class Maths Textbook Solutions are the standard method used across all CBSE schools.

The solution covers every chapter included in the CBSE Class 6 Maths textbook. These include:

Chapter 1 – Knowing Our Numbers

Chapter 2 – Whole Numbers

Chapter 3 – Playing with Numbers

Chapter 4 – Basic Geometrical Ideas

Chapter 5 – Understanding Elementary Shapes

Chapter 6 – Integers

Chapter 7 – Fractions

Chapter 8 – Decimals

Chapter 9 – Data Handling

Chapter 10 – Mensuration

Chapter 11 – Algebra

Chapter 12 – Ratio and Proportion

Chapter 13 – Symmetry

Chapter 14 – Practical Geometry

Vedantu: Your Go-to Study Partner

Vedantu provides a vast assortment of study materials in an easy and comprehensive manner for all subjects. Students can avail of the NCERT Solutions for Class 6 Maths and other subjects in PDF format from the Vedantu website for free.

Students can have hassle-free access to these solutions from anywhere on the go. They do not have to register with Vedantu to utilize the study materials.

Along with free access, students can also download these PDF solutions on cell phones to read them offline.

These solutions are crafted as per the syllabus prescribed by CBSE so students can avail of the latest study materials quickly and easily.

So, download your NCERT Solutions for Class 6 Maths and other subjects now to ace your upcoming examinations.

FAQs on NCERT Solutions for Class 6 Maths Chapter 1: Knowing our Numbers - Exercise 1.1

1. What is asked in the exercise questions of Class 6 Maths Chapter 1 Knowing Our Numbers Exercise 1.1?

In the first question of the Class 6 Maths textbook Chapter 1 Ex 1.1., students are asked to fill in the blanks based on their knowledge of the number conversion from one Numeration method to another. In the second question, students are asked to write the corresponding numerical value of the numbers written with words along with commas at the right place. The third question is given without comma splicing and students are asked to put commas as per the Indian System of Numeration. As per the fourth questions, students are asked to rewrite the numbers according to their International Numeric System.

2. Where can I find exercise-wise NCERT Solutions for Class 6 Mathematics Chapter 1?

Students can find exercise-wise NCERT Solutions for Class 6 Maths Chapter 1 on Vedantu, a premier e-learning solution. These solutions are designed as per the NCERT guidelines and exam pattern. Students can find the free downloadable PDFs of Exercise 1.1 and other exercises of Class 6 Maths Chapter 1. These materials are prepared by subject matter experts at Vedantu and help score well in the paper.

3. What does Chapter 1 Knowing Our Numbers of Class 6 Maths deal with?

Knowing Our Numbers, the first chapter of Class 6 NCERT Mathematics textbook, teaches students how to compare two or more numbers. It also makes students aware of both the system of numeration (Indian and International). It teaches them how to read numbers and use commas as per these systems. Knowing Our Numbers is an interesting chapter that makes students capable of reading and writing large numbers correctly.

4. How to express numbers in the Indian System of Numeration?

As per the Indian System of Numeration, the figures like tens, hundreds, thousands, lakhs and crores are used. Commas are used to mark thousands, lakhs and crores. The first comma is used after hundred’s place, the second comma comes after the fifth digit from right, third comes after the seventh digit and so on. For example- 6, 09, 20, 563 which will be read as Six Crores Nine Lakhs Twenty Thousand Five Hundred and Sixty-three.

5. Where can I avail myself of the Solutions for Class 6 Maths Chapter 1 Exercise 1.1?

The solutions are easily available on the Vedantu site. You can follow these steps to avail them:

Click on this link

The webpage with Vedantu’s solutions for Class 6 Maths Chapter 1 Exercise 1.1 will open.

To download this, click on the Download PDF button and you can view the solutions offline.

6. How many problems are there in each exercise of NCERT Solutions for Class 6 Maths Chapter 1?

Each exercise of Chapter 1 of NCERT Class 6 has its own different set of exercises spanning across different topics related to the content taught in the chapters. For the solutions of these exercises, one can easily access them from Solutions of the NCERT Mathematics textbook of Class 6 Chapter 1 and download the PDF version without any cost. The solutions provided by Vedantu are free of cost and are also available on the Vedantu Mobile app.

7. Is NCERT Class 6 Maths Chapter 1 easy?

The First Chapter is a bit enjoyable if you understand the methods as it starts off with the basics. But as you progress, things may get perplexing because there are various ways to answer a question or problem. The chapters of Class 6 are basic but vast, and it's easy to become lost in all the formulas and derivations. However, with enough practice, you will be able to ace every exam with flying colours.

8. What do prime numbers mean?

There are two factors in a prime number – themselves and 1. When dividing a prime number, no remainder is obtained. 17 is a prime number. 1 and 17 are the only possible factors. Because it has just one factor (1), 1 isn't considered a prime number. There are a total of 25 prime numbers from 1 to 100. It is important to have a basic knowledge about prime numbers as well as the other different types of numbers.

9. What concepts do Chapter 1 of NCERT Class 6 Maths emphasise on?

Introduction and Comparing Numbers are the two primary sub-topics. Students will study a variety of number-related features, such as how to compare numbers, how to write numbers with commas, how to construct multiple numbers from a set of digits, how to find the biggest and smallest numbers, and so on. Students will also learn how to use commas and read and write big figures.

NCERT Solutions for Class 6

Cbse study materials for class 6, cbse study materials.

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Latest Chapter Wise Extra Questions for Class 6 Mathematics

Latest Chapter Wise Extra Questions for Class 6 Mathematics myCBSEguide has just released Chapter Wise Question Answers for class 6 Maths. These Extra Questions with solution are prepared by our team of expert teachers who are teaching grade in CBSE schools for years. There are around 4-5 set of solved Mathematics Extra questions from each and every chapter. The students will not miss any concept in these Chapter wise question that are specially designed to tackle Exam. We have taken care of every single concept given in CBSE Class 6 Mathematics syllabus and questions are framed as per the latest marking scheme and blue print issued by CBSE for Class 6. These chapter wise Practice Questions with complete solutions are available for download in myCBSEguide website and mobile app.

Chapter Wise Important Questions for Class 6 Mathematics

Knowing our Numbers
Whole Numbers
Playing with Numbers
Basic Geometrical Ideas
Understanding Elementary Shapes
Data handling
Mensuration
Ratio and Proportion
Practical Geometry

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CBSE Case Study Questions for Class 6 – 10, 12 for Maths, Science, SST

Cbse case study questions for maths, science, social science.

CBSE Case Study Questions: Case Study Questions for all Class 1, 2, 4, 5, 6, 7, 8, 9,10, 11 and 12 by Experienced Teachers. We Net Ex. Arranged here Important Case Based Questions for CBSE Board – Maths, Science, Social Science, English.

One must keep in mind to not discover the answers straight forwardly within the given entry but moreover think effectively to determine the answer. Case based questions are either MCQs or Attestation Reason Questions, so for endeavoring such questions you must take after the run the show of end. Case studies capture a range of perspectives, as opposed to the single view of an individual you get with a survey response or interview. This gives the opportunity to gain a greater understanding of the subject in hand and reduces the potential for any bias, by diluting the agenda of a particular individual.

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Due to a little test, the case ponder can conduct an in-depth investigation. – Case ponders make openings for a wealthy surrender of information, and the profundity of investigation can in turn bring tall levels of legitimacy (i.e. giving an exact and comprehensive degree of what the think about is trusting to degree).

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