homework 2 4 angles of triangles

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Course: 8th grade   >   Unit 5

• Angles in a triangle sum to 180° proof
• Find angles in triangles
• Isosceles & equilateral triangles problems
• Find angles in isosceles triangles
• Triangle exterior angle example
• Worked example: Triangle angles (intersecting lines)
• Worked example: Triangle angles (diagram)
• Finding angle measures using triangles
• Triangle angle challenge problem
• Triangle angle challenge problem 2

Triangle angles review

Sum of interior angles in triangles.

109 ∘ + 23 ∘ + 48 ∘ = 180 ∘ ‍  

Finding a missing angle

x ∘ + 42 ∘ + 106 ∘ = 180 ∘ ‍  

x ∘ = 180 ∘ − 106 ∘ − 42 ∘ ‍   x = 32 ‍  

• Your answer should be
• an integer, like 6 ‍  
• a simplified proper fraction, like 3 / 5 ‍  
• a simplified improper fraction, like 7 / 4 ‍  
• a mixed number, like 1   3 / 4 ‍  
• an exact decimal, like 0.75 ‍  
• a multiple of pi, like 12   pi ‍   or 2 / 3   pi ‍  

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Chapter 4, Lesson 2: Angles of Triangles

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1.0: Angles and Triangles

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• Page ID 112400

• Katherine Yoshiwara
• Los Angeles Pierce College

Historically, trigonometry began as the study of triangles and their properties. Let’s review some definitions and facts from geometry.

• We measure angles in degrees.
• One full rotation is \(360^{\circ}\), as shown below.
• Half a full rotation is \(180^{\circ}\) and is called a straight angle .
• One quarter of a full rotation is \(90^{\circ}\) and is called a right angle .

If you tear off the corners of any triangle and line them up, as shown below, they will always form a straight angle.

Sum of angles in a triangle.

1. The sum of the angles in a triangle is \(180^{\circ}\).

Example 1.1

Two of the angles in the triangle at right are \(25^{\circ}\) and \(115^{\circ}\). Find the third angle.

To find the third angle, we write an equation.

\begin{aligned} x+25+115 &=180 \quad \quad &&\text{Simplify the left side.} \\ x+140 &=180 \quad \quad &&\text{Subtract 140 from both sides.}\\ x &=40 \end{aligned}

The third angle is \(40^{\circ}\).

Checkpoint 1.2

Find each of the angles in the triangle at right.

\(x = 39^{\circ}, 2x = 78^{\circ}, 2x-15 = 63^{\circ}\)

Some special categories of triangles are particularly useful. Most important of these are the right triangles .

Right triangle.

2. A right triangle has one angle of \(90^{\circ}\).

Example 1.3

One of the smaller angles of a right triangle is \(34^{\circ}\). What is the third angle?

The sum of the two smaller angles in a right triangle is \(90^{\circ}\). So

\begin{aligned} x+34 &=90 \quad \quad \text{Subtract 34 from both sides} \\ x &=56 \end{aligned}

The unknown angle must be \(56^{\circ}\).

Checkpoint 1.4

Two angles of a triangle are \(35^{\circ}\) and \(45^{\circ}\). Can it be a right triangle?

An equilateral triangle has all three sides the same length.

Angles of equilateral triangle.

3. All of the angles of an equilateral triangle are equal.

Example 1.5

All three sides of a triangle are 4 feet long. Find the angles.

The triangle is equilateral, so all of its angles are equal. Thus

\begin{aligned} 3 x &=180 \quad \quad \quad \text{Divide both sides by 3.}\\ x &=60 \end{aligned}

Each of the angles is \(60^{\circ}\).

Checkpoint 1.6

Find \(x, y\), and \(z\) in the triangle at right.

\(x=60^{\circ}, y=8, z=8\)

An isosceles triangle has two sides of equal length. The angle between the equal sides is the vertex angle . The other two angles are the base angles.

Base angles of an isoceles triangle.

4. The base angles of an isosceles triangle are equal.

Example 1.7

Find \(x\) and \(y\) in the triangle at right.

The triangle is isosceles, so the base angles are equal. Therefore, \(y=38^{\circ}\). To find the vertex angle, we solve

\begin{aligned} x+38+38 &=180 \\ x+76 &=180 \quad \quad \quad \text{Subtract 76 from both sides.}\\ x &=104 \end{aligned}

The vertex angle is \(104^{\circ}\).

Checkpoint 1.8

Find \(x\) and \(y\) in the figure at right.

\(x=140^{\circ}, y=9\)

In addition to the facts about triangles reviewed above, there are several useful properties of angles.

• Two angles that add to \(180^{\circ}\) are called supplementary .
• Two angles that add to \(90^{\circ}\) are called complementary .
• Angles between \(0^{\circ}\) and \(90^{\circ}\) are called acute .
• Angles between \(90^{\circ}\) and \(180^{\circ}\) are called obtuse .

Example 1.9

In the figure at right,

• \(\angle A O C\) and \(\angle B O C\) are supplementary.
• \(\angle D O E\) and \(\angle B O E\) are complementary.
• \(\angle A O C\) is obtuse,
• and \(\angle B O C\) is acute.

In trigonometry we often use lower-case Greek letters to represent unknown angles (or, more specifically, the measure of the angle in degrees). In the next Exercise, we use the Greek letters \(\alpha\) (alpha), \(\beta\) (beta), and \(\gamma\) (gamma).

Checkpoint 1.10

In the figure, \(\alpha, \beta\), and \(\gamma\) denote the measures of the angles in degrees.

a. Find the measure of angle \(\alpha\). b. Find the measure of angle \(\beta\). c. Find the measure of angle \(\gamma\). d. What do you notice about the measures of the angles?

\(\quad \alpha=130^{\circ}, \beta=50^{\circ}, \gamma=130^{\circ}\). The non-adjacent angles are equal.

Non-adjacent angles formed by the intersection of two straight lines are called vertical angles . In the previous exercise, the angles labeled \(\alpha\) and \(\gamma\) are vertical angles, as are the angles labeled \(\beta\) and \(50^{\circ}\).

Vertical Angles.

5. Vertical angles are equal.

Example 1.11

Explain why \(\alpha=\beta\) in the triangle at right.

Because they are the base angles of an isosceles triangle, \(\theta\) (theta) and \(\phi(\mathrm{phi})\) are equal. Also, \(\alpha=\theta\) because they are vertical angles, and similarly \(\beta=\phi\). Therefore, \(\alpha=\beta\) because they are equal to equal quantities.

Checkpoint 1.12

Find all the unknown angles in the figure at right. (You will find a list of all the Greek letters and their names at the end of this section.)

\(\alpha=40^{\circ}, \beta=140^{\circ}, \gamma=75^{\circ}, \delta=65^{\circ}\)

A line that intersects two parallel lines forms eight angles, as shown in the figure below. There are four pairs of vertical angles, and four pairs of corresponding angles , or angles in the same position relative to the transversal on each of the parallel lines.

For example, the angles labeled 1 and 5 are corresponding angles, as are the angles labeled 4 and 8. Finally, angles 3 and 6 are called alternate interior angles , and so are angles 4 and 5.

Parallel lines cut by a transversal.

6. If parallel lines are intersected by a transversal, the alternate interior angles are equal. Corresponding angles are also equal.

Example 1.13

The parallelogram \(A B C D\) shown at right is formed by the intersection of two sets of parallel lines. Show that the opposite angles of the parallelogram are equal.

Angles 1 and 2 are equal because they are alternate interior angles, and angles 2 and 3 are equal because they are corresponding angles. Therefore angles 1 and 3 , the opposite angles of the parallelogram, are equal. Similarly, you can show that angles 4,5 , and 6 are equal.

Checkpoint 1.14

Show that the adjacent angles of a parallelogram are supplementary. (You can use angles 1 and 4 in the parallelogram of the previous example.)

Note that angles 2 and 6 are supplementary because they form a straight angle. Angle 1 equals angle 2 because they are alternate interior angles, and similarly angle 4 equals angle 5. Angle 5 equals angle 6 because they are corresponding angles. Thus, angle 4 equals angle 6, and angle 1 equals angle 2. So angles 4 and 1 are supplementary because 2 and 6 are.

Note 1.15 In the Section 1.1 Summary, you will find a list of vocabulary words and a summary of the facts from geometry that we reviewed in this section. You will also find a set of study questions to test your understanding, and a list of skills to practice in the homework problems.

Table 1.16 Lower Case Letters in the Greek Alphabet

\begin{aligned} &\quad \quad \quad \quad \quad \text { Greek Alphabet }\\ &\begin{array}{cc|cc|cc|} \hline \alpha & \text { alpha } & \beta & \text { beta } & \gamma & \text { gamma } \\ \hline \delta & \text { delta } & \epsilon & \text { epsilon } & \gamma & \text { gamma } \\ \hline \eta & \text { eta } & \theta & \text { theta } & \iota & \text { iota } \\ \hline \kappa & \text { kappa } & \lambda & \text { lambda } & \mu & \text { mu } \\ \hline \nu & \text { nu } & \xi & \text { xi } & o & \text { omicron } \\ \hline \pi & \text { pi } & \rho & \text { rho } & \sigma & \text { sigma } \\ \hline \tau & \text { tau } & v & \text { upsilon } & \phi & \text { phi } \\ \hline \chi & \text { chi } & \psi & \text { psi } & \omega & \text { omega } \\ \hline \end{array} \end{aligned}

Review the following skills you will need for this section.

Algebra Refresher 1.2

Solve the equation.

1. \(x-8=19-2 x\) 2. \(2 x-9=12-x\) 3. \(13 x+5=2 x-28\) 4. \(4+9 x=-7+x\)

Solve the system.

5. \(5x - 2y = -13\)

\(2x + 3y = -9\)

6. \(4x + 3y = 9\)

\(3x + 2y = 8\)

5. \(x=-3,y=-1\)

6. \(x=6,y=-5\)

Section 1.1 Summary

• Right angle

• Straight angle

• Right triangle

• Equilateral triangle

• Isosceles triangle

• Vertex angle

• Base angle

• Supplementary

• Complementary

• Acute

• Obtuse

• Vertical angles

• Transversal

• Corresponding angles

• Alternate interior angles

Facts from Geometry.

1. The sum of the angles in a triangle is \(180^{\circ}\). 2. A right triangle has one angle of \(90^{\circ}\). 3. All of the angles of an equilateral triangle are equal. 4. The base angles of an isosceles triangle are equal. 5. Vertical angles are equal. 6. If parallel lines are intersected by a transversal, the alternate interior angles are equal.

Corresponding angles are also equal.

Study Questions

1. Is it possible to have more than one obtuse angle in a triangle? Why or why not?

2. Draw any quadrilateral (a four-sided polygon) and divide it into two triangles by connecting two opposite vertices by a diagonal. What is the sum of the angles in your quadrilateral?

3. What is the difference between a vertex angle and vertical angles?

4. Can two acute angles be supplementary?

5. Choose any two of the eight angles formed by a pair of parallel lines cut by a transversal. Those two angles are either equal or _______ .

Practice each skill in the Homework Problems listed.

1. Sketch a triangle with given properties #1–6

2. Find an unknown angle in a triangle #7–12, 17–20

3. Find angles formed by parallel lines and a transversal #13–16, 35–44

4. Find exterior angles of a triangle #21–24

5. Find angles in isosceles, equilateral, and right triangles #25–34

6. State reasons for conclusions #45–48

Homework 1.1

For Problems 1–6, sketch and label a triangle with the given properties.

1. An isosceles triangle with vertex angle \(30^{\circ}\) 2. A scalene triangle with one obtuse angle ( Scalene means three unequal sides.) 3. A right triangle with \(\operatorname{legs} 4\) and 7 4. An isosceles right triangle 5. An isosceles triangle with one obtuse angle 6. A right triangle with one angle \(20^{\circ}\)

For Problems 7–20, find each unknown angle.

In Problems 21 and 22, the angle labeled \(\phi\) is called an exterior angle of the triangle, formed by one side and the extension of an adjacent side. Find \(\phi\).

23. In parts (a) and (b), find the exterior angle \(\phi\).

c. Find an algebraic expression for \(\phi\).

d Use your answer to part (c) to write a rule for finding an exterior angle of a triangle.

a Find the three exterior angles of the triangle. What is the sum of the exterior angles?

b Write an algebraic expression for each exterior angle in terms of one of the angles of the triangle. What is the sum of the exterior angles?

In Problems 25 and 26, the figures inscribed are regular polygons , which means that all their sides are the same length, and all the angles have the same measure. Find the angles \(\theta\) and \(\phi\).

In problems 27 and 28, \(\Delta ABC\) is equilateral. Find the unknown angles

a \(2\theta + 2\phi = ________\)

b \(\theta + \phi = ________\)

c \(\Delta ABC\) is ________

30. Find \(\alpha\) and \(\beta\).

a Explain why \(\angle O A B\) and \(\angle A B O\) are equal in measure.

b Explain why \(\angle O B C\) and \(\angle B C O\) are equal in measure.

c Explain why \(\angle A B C\) is a right angle. (Hint: Use Problem 29.)

a Compare \(\theta\) with \(\alpha+\beta\). (Hint: What do you know about supplementary angles and the sum of angles in a triangle?

b Compare \(\alpha\) and \(\beta\).

c Explain why the inscribed angle \(\angle B A O\) is half the size of the central angle \(\angle B O D\).

33. Find \(\alpha\) and \(\beta\).

34. Find \(\alpha\) and \(\beta\).

In Problems 35–44, arrows on a pair of lines indicate that they are parallel. Find \(x\) and \(y\).

a Among the angles labeled 1 through 5 in the figure at right, find two pairs of equal angles.

b \(\angle 4+\angle 2+\angle 5= _________\)

c Use parts (a) and (b) to explain why the sum of the angles of a triangle is \(180^{\circ}\)

a In the figure below, find \(\theta\), and justify your answer.

b Write an algebraic expression for \(\theta\) in the figure below.

47. \(A B C D\) is a rectangle. The diagonals of a rectangle bisect each other. In the figure, \(\angle A Q D=130^{\circ}\). Find the angles labeled 1 through 5 in order, and give a reason for each answer.

48. A tangent meets the radius of a circle at a right angle. In the figure, \(\angle AOB = 140^{\circ}\). Find the angles labeled 1 through 5 in order, and give a reason for each answer.

Chapter 1: Triangles and Circles

Exercises: 1.1 Triangles and Angles

Practice each skill in the Homework Problems listed.

• Sketch a triangle with given properties #1–6
• Find an unknown angle in a triangle #7–12, 17–20
• Find angles formed by parallel lines and a transversal #13–16, 35–44
• Find exterior angles of a triangle #21–24
• Find angles in isosceles, equilateral, and right triangles #25–34
• State reasons for conclusions #45–48

Suggested Problems

Exercises for 1.1 Triangles and Angles

Exercise group, 1. an isosceles triangle with a vertex angle [latex]306^{\circ}[/latex], 2. a scalene triangle with one obtuse angle ( scalene means three unequal sides.), 3. a right triangle with legs [latex]4[/latex] and [latex]7[/latex], 4. an isosceles right triangle, 5. an isosceles triangle with one obtuse angle, 6. a right triangle with one angle [latex]20°[/latex].

In parts (a) and (b), find the exterior angle [latex]\phi[/latex].

• Use your answer to part (c) to write a rule for finding an exterior angle of a triangle.

In Problems 25 and 26, the figures inscribed are regular polygons , which means that all their sides are the same length, and all the angles have the same measure. Find the angles [latex]\theta[/latex] and [latex]\phi[/latex].

In problems 27 and 28, triangle ABC is equilateral. Find the unknown angles.

a. [latex]2\theta + 2\phi =[/latex]

b. [latex]\theta + \phi =[/latex]

c. [latex]\triangle ABC[/latex] is

Find [latex]\alpha[/latex] and [latex]\beta[/latex]

• Explain why [latex]\angle OAB[/latex] and [latex]\angle ABO[/latex] are equal in measure.
• Explain why [latex]\angle OBC[/latex] and [latex]\angle BCO[/latex] are equal in measure.
• Explain why [latex]\angle ABC[/latex] is a right angle. (Hint: Use Problem 29.)
• Compare [latex]\theta[/latex] with [latex]\alpha + \beta[/latex] (Hint: What do you know about supplementary angles and the sum of angles in a triangle?)
• Compare [latex]\alpha[/latex] and [latex]\beta[/latex]
• Explain why the inscribed angle [latex]\angle BAO[/latex] is half the size of the central angle [latex]\angle BOD[/latex]

Find [latex]\alpha[/latex] and [latex]\beta[/latex]

• [latex]\angle 4 + \angle 2 + \angle 5 =[/latex]
• Use parts (a) and (b) to explain why the sum of the angles of a triangle is [latex]180^{\circ}[/latex]

ABCD is a rectangle. The diagonals of a rectangle bisect each other. In the figure,  [latex]\angle AQD = 130^{\circ}[/latex]. Find the angles labeled 1 through 5 in order, and give a reason for each answer.

A tangent meets the radius of a circle at a right angle. In the figure, [latex]\angle AOB = 140^{\circ}[/latex]. Find the angles labeled 1 through 5 in order, and give a reason for each answer.

Trigonometry Copyright © 2024 by Bimal Kunwor; Donna Densmore; Jared Eusea; and Yi Zhen. All Rights Reserved.

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Triangle Angle Calculator

Table of contents

Triangle angle calculator is a safe bet if you want to know how to find the angle of a triangle. Whether you have three sides of a triangle given, two sides and an angle or just two angles, this tool is a solution to your geometry problems. Below you'll also find the explanation of fundamental laws concerning triangle angles: triangle angle sum theorem, triangle exterior angle theorem, and angle bisector theorem. Read on to understand how the calculator works, and give it a go - finding missing angles in triangles has never been easier!

How to find the angle of a triangle

There are several ways to find the angles in a triangle, depending on what is given:

• Given three triangle sides

Use the formulas transformed from the law of cosines:

For the second angle we have:

And eventually, for the third angle:

• Given two triangle sides and one angle

If the angle is between the given sides, you can directly use the law of cosines to find the unknown third side, and then use the formulas above to find the missing angles, e.g. given a,b,γ:

• calculate c = a 2 + b 2 − 2 a b × cos ⁡ ( γ ) c = \sqrt{a^2 + b^2 - 2ab \times \cos(\gamma)} c = a 2 + b 2 − 2 ab × cos ( γ ) ​ ;
• substitute c c c in α = a r c c o s ( ( b 2 + c 2 − a 2 ) / ( 2 b c ) ) \alpha = \mathrm{arccos}\left((b^2 + c^2- a^2)/(2bc)\right) α = arccos ( ( b 2 + c 2 − a 2 ) / ( 2 b c ) ) ;
• then find β \beta β from triangle angle sum theorem: β = 180 ° − α − γ \beta = 180\degree- \alpha - \gamma β = 180° − α − γ

If the angle isn't between the given sides, you can use the law of sines. For example, assume that we know a a a , b b b , and α \alpha α :

• As you know, the sum of angles in a triangle is equal to 180 ° 180\degree 180° . From this theorem we can find the missing angle: γ = 180 ° − α − β \gamma = 180\degree- \alpha - \beta γ = 180° − α − β .
• Given two angles

That's the easiest option. Simply use the triangle angle sum theorem to find the missing angle:

• α = 180 ° − β − γ \alpha = 180\degree- \beta - \gamma α = 180° − β − γ ;
• β = 180 ° − α − γ \beta= 180\degree- \alpha - \gamma β = 180° − α − γ ; and
• γ = 180 ° − α − β \gamma = 180\degree- \alpha- \beta γ = 180° − α − β

In all three cases, you can use our triangle angle calculator - you won't be disappointed.

🙋 Meet the law of sines and cosines at our law of cosines calculator and law of sines calculator ! Everything will be clear afterward. 😉

Sum of angles in a triangle - Triangle angle sum theorem

The theorem states that interior angles of a triangle add to 180 ° 180\degree 180° :

How do we know that? Look at the picture: the angles denoted with the same Greek letters are congruent because they are alternate interior angles. Sum of three angles α \alpha α β \beta β , γ \gamma γ is equal to 180 ° 180\degree 180° , as they form a straight line. But hey, these are three interior angles in a triangle! That's why α + β + γ = 180 ° \alpha + \beta+ \gamma = 180\degree α + β + γ = 180° .

Exterior angles of a triangle - Triangle exterior angle theorem

An exterior angle of a triangle is equal to the sum of the opposite interior angles .

• Every triangle has six exterior angles (two at each vertex are equal in measure).
• The exterior angles, taken one at each vertex, always sum up to 360 ° 360\degree 360° .
• An exterior angle is supplementary to its adjacent triangle interior angle.

Angle bisector of a triangle - Angle bisector theorem

Angle bisector theorem states that:

An angle bisector of a triangle angle divides the opposite side into two segments that are proportional to the other two triangle sides.

Or, in other words:

The ratio of the B D ‾ \overline{BD} B D length to the D C ‾ \overline{DC} D C length is equal to the ratio of the length of side A B ‾ \overline{AB} A B to the length of side A C ‾ \overline{AC} A C :

Finding missing angles in triangles - example

OK, so let's practice what we just read. Assume we want to find the missing angles in our triangle. How to do that?

• Find out which formulas you need to use . In our example, we have two sides and one angle given. Choose angle and 2 sides option.
• Type in the given values . For example, we know that a = 9   i n a = 9\ \mathrm{in} a = 9   in , b = 14   i n b = 14\ \mathrm{in} b = 14   in , and α = 30 ° \alpha = 30\degree α = 30° . If you want to calculate it manually, use law of sines:
• From the theorem about sum of angles in a triangle, we calculate that γ = 180 ° − α − β = 180 ° − 30 ° − 51.06 ° = 98.94 ° \gamma = 180\degree- \alpha - \beta = 180\degree- 30\degree - 51.06\degree= 98.94\degree γ = 180° − α − β = 180° − 30° − 51.06° = 98.94° .
• The triangle angle calculator finds the missing angles in triangle . They are equal to the ones we calculated manually: β = 51.06 ° \beta = 51.06\degree β = 51.06° , γ = 98.94 ° \gamma = 98.94\degree γ = 98.94° ; additionally, the tool determined the last side length: c = 17.78   i n c = 17.78\ \mathrm{in} c = 17.78   in .

Reasoning similar to the one we applied in this calculator appears in other triangle calculations, for example the ones we use in the ASA triangle calculator and the SSA triangle calculator !

How do I find angles in a triangle?

To determine the missing angle(s) in a triangle, you can call upon the following math theorems:

• The fact that the sum of angles is a triangle is always 180° ;
• The law of cosines ; and
• The law of sines .

Which set of angles can form a triangle?

Every set of three angles that add up to 180° can form a triangle. This is the only restriction when it comes to building a triangle from a given set of angles.

Why can't a triangle have more than one obtuse angle?

This is because the sum of angles in a triangle is always equal to 180° , while an obtuse angle has more than 90° degrees. If you had two or more obtuse angles, their sum would exceed 180° and so they couldn't form a triangle. For the same reason, a triangle can't have more than one right angle!

How do I find angles of the 3 4 5 triangle?

Let's denote a = 5 , b = 4 , c = 3 .

• Write down the law of cosines 5² = 3² + 4² - 2×3×4×cos(α) . Rearrange it to find α , which is α = arccos(0) = 90° .
• You can repeat the above calculation to get the other two angles.
• Alternatively, as we know we have a right triangle, we have b/a = sin β and c/a = sin γ .
• Either way, we obtain β ≈ 53.13° and γ ≈ 36.87 .
• We quickly verify that the sum of angles we got equals 180° , as expected.

Angle selection

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